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Vedmedyk [2.9K]
3 years ago
9

Solution that has a ph below 7.0 tastes sour is called

Chemistry
1 answer:
svet-max [94.6K]3 years ago
5 0
That would be  an acid.
You might be interested in
A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil
Flura [38]

Answer:  Molarity of Cl^- anions in the chemist's solution is 0.0104 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles  

V_s = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L

Therefore, the molarity of solution will be 5.2\times 10^{-3}mole/L

MgCl_2\rightarrow Mg^{2+}+2Cl^-

As 1 mole of MgCl_2 gives 2 moles of Cl^-

Thus 5.2\times 10^{-3}  moles of MgCl_2 gives =\frac{2}{1}\times 5.2\times 10^{-3}=0.0104

Thus the molarity of Cl^- anions in the chemist's solution is 0.0104 M

6 0
3 years ago
Really strong acids and bases are found at the​
makkiz [27]

Ends....................?

4 0
3 years ago
Draw the structure of tofacitinib with explicitly shown all carbon and hydogen atoms. identify the number of carbon atoms in tof
Andrew [12]

The structure of tofacitinib with explicit carbon and hydrogen is the first attached picture.

The number of carbon atoms in tofacitinib are 16.

The molecular formula of tofacitinib is C_{16}H_{20}N_{6}O.

The structure of tofacitinib with all the filled hydrogen atoms is the second attached picture.

3 0
3 years ago
2 point
Luden [163]

Answer:

21

Explanation:

7 0
3 years ago
An experiment reveals that 125.0 grams of an unknown metal increases in temperature from 22.0 oC to 43.6 oC upon absorbing 640 j
nydimaria [60]

Answer:

                     Cp  =  0.237 J.g⁻¹.°C⁻¹

Explanation:

                      Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  640 J

           m  =  mass  =  125 g

           Cp  =  Specific Heat Capacity  =  <u>??</u>

           ΔT  =  Change in Temperature  =  43.6 °C  -  22 °C  =  21.6 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  640 J / (125 g × 21.6 °C)

                                Cp  =  0.237 J.g⁻¹.°C⁻¹

3 0
3 years ago
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