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Vika [28.1K]
4 years ago
7

5. Suppose a skydiver (mass = 75kg) is falling toward the Earth. When the skydiver is 100m above the Earth he is moving at 60m/s

. At this point calculate the skydiver’s…….Show your work and answer: PE=mgh M= G= H=
Physics
1 answer:
Anna71 [15]4 years ago
3 0

1) Gravitational potential energy: 73 500 J

2) Kinetic energy: 135 000 J

3) Mechanical energy: 208 500 J

Explanation:

1)

The gravitational potential energy of an object is the energy possessed by the object due to its position in the Earth's gravitational field, and it is given by

U=mgh

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity

h is the height of the object relative to the ground

For the skydiver in this problem,

m = 75 kg is his mass

h = 100 m is his height above the Earth

Substituting, we find

U=(75)(9.8)(100)=73500 J

2)

The kinetic energy of a body is the energy due to its motion, and it is given by

K=\frac{1}{2}mv^2

where

m is the mass of the body

v is its speed

For the skydiver in this problem,

m = 75 kg is his mass

v = 60 m/s is his speed

Substituting, we find the kinetic energy

K=\frac{1}{2}(75)(60)^2=135000 J

3)

The mechanical energy of an object is the sum of the gravitational potential energy and the kinetic energy of the object:

E=U+K

where

U is the gravitational potential energy

K is the kinetic energy

For the skydiver in this problem,

U = 73,500 J is the gravitational potential energy

K = 135,000 J is the kinetic energy

Substituting, we find

E=73,500 + 135,000 = 208,500 J

Learn more about potential energy and kinetic energy:

brainly.com/question/1198647

brainly.com/question/10770261

brainly.com/question/6536722

#LearnwithBrainly

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Answer:

1) Transition states are short-lived

Explanation:

Transition state theory explains the rates of elementary chemical reactions. It assumes a quasi-equilibrium between reactants and activated transition state complexes.

The following are the characteristics of transition states

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98 POINTS, 5 simple questions!! HELP
lozanna [386]

25,000 Feet = 7620m

PE = mgh where m is mass, g is gravity accel: 9.8 n h is height

= 90 x 9.8 x 7620

= 6720840J

= 6.72MJ

F = ma where m is mass, a is accel = gravity = 9.8

= 90 x 9.8

= 882N

Accel = gravity = 9.8m/s^2

KE = 1/2mv^2 where m is mass n v is vel

if no wind resistance, PE leaving airplane = KE at net

6720840 = 1/2 x 90 x v^2

v^2 = 149352

v = 386.5m/s


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How much current must be applied across a 60 Ω light bulb filament in order for it to consume 55 W of power? Unserious answers w
sergij07 [2.7K]

Answer: current I = 0.96 Ampere

Explanation:

Given that the

Resistance R = 60 Ω 

Power = 55 W

Power is the product of current and voltage. That is

P = IV ...... (1)

But voltage V = IR. From ohms law.

Substitutes V in equation (1) power is now

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Substitute the above parameters into the formula to get current I

55 = 60 × I^2

Make I^2 the subject of formula

I^2 = 55/60

I^2 = 0.92

I = sqr(0.92)

I = 0.957 A

Therefore, 0.96 A current must be applied.

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