A 50-kg box is being pushed a distance of 8.0 m across the floor by a force P with arrow whose magnitude is 159 N. The force P w
1 answer:
Answer:
Wp = 1,272 J
Wf = -940.8 J
Wn = 0
Wg = 0
Explanation:
- Applying the definition of work, as the product of the component of the force applied, along the direction of the displacement, times the displacement, we find that due to the normal force is always perpendicular to the surface, it does no work, as it has not a component in the direction of the displacement, so Wn = 0.
- As the weight goes directly downward, it has no component in the direction of the displacement either, so Wg = 0.
- We can get the work done by the force applied P, simply as follows:
- Finally, we have the work done by the force of friction that always opposes to the displacement, so it has negative sign.
- The frictional force , can be written as follows:
where μk = coefficient of kinetic friction = 0.24
Fn = Normal Force
- In this case, since the surface is level and horizontal, and there is no acceleration of the box in the vertical direction, this means that the normal force (in magnitude) must be equal to the weight:
- Fn = m*g = 50 kg * 9.8 m/s2 = 490 N
- Replacing these values in (2), we get:
- Applying the definition of work, we can get the work done by the frictional force, as follows:
You might be interested in
Answer:
Explanation:
According to the free-body diagram of the system, we have:
So, we can solve for T from (1):
Replacing (3) in (2):
The electric force () is given by the Coulomb's law. Recall that the charge q is the same in both spheres:
According to pythagoras theorem, the distance of separation (r) of the spheres are given by:
Finally, we replace (5) in (4) and solving for q:
Answer:
-4.0 N
Explanation:
Since the force of friction is the only force acting on the box, according to Newton's second law its magnitude must be equal to the product between mass (m) and acceleration (a):
(1)
We can find the mass of the box from its weight: in fact, since the weight is W = 50.0 N, its mass will be
And we can fidn the acceleration by using the formula:
where
v = 0 is the final velocity
u = 1.75 m/s is the initial velocity
t = 2.25 s is the time the box needs to stop
Substituting, we find
(the acceleration is negative since it is opposite to the motion, so it is a deceleration)
Therefore, substituting into eq.(1) we find the force of friction:
Where the negative sign means the direction of the force is opposite to the motion of the box.