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andrew-mc [135]
3 years ago
15

Where would outdoor Air quality monitors need to be placed to properly record data?

Engineering
1 answer:
weqwewe [10]3 years ago
3 0

it is ideal to place indoor sensors near the typical breathing zone height (3 – 6 ft). They should be placed away from air pollution sources, like a toaster, and air pollution sinks, like air cleaners, to get a more representative measure of indoor air quality.

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Imagine you have to create a pet robot that responds to touch. When someone touches or pets the head of the robot, the LED light
AysviL [449]

Answer:

ive been stuck on this for 30 minutes bro

Explanation:

7 0
3 years ago
Sed is a multipurpose tool that combines the work of several filters. sed performs noninteractive operations on a data stream. s
timama [110]

Answer:

The answer is True.

Explanation:

SED is a command in UNIX for stream editors that parses and transforms text, using a simple, compact programming language. So the answer is TRUE that sed is a multipurpose tool that combines the work of several filters and performs noninteractive operations on a data stream. sed has a host of features that allow you ti select lines and run instructions on them.

6 0
3 years ago
Emily Kent works as a computer progra mmer for a software company. Her boss, Sam Anderson, is responsible for developing a new s
matrenka [14]

Answer:

A pirated software

Explanation:

Software piracy is a term used to describe the act of illegally using, copying, distributing, modifying or selling software without ownership or legal rights. When unauthorized individual uses or accesses a software products and services, then the software is pirated.

Since Sam is giving all the team members a (free) copy of the game without (consent) from the company, it is illegal and termed pirated software

8 0
4 years ago
A full visual analysis would require that a product be dismantled completely so that all of its components can be described.
Schach [20]
True, you need to be able to see all parts of the object to visualize it
6 0
3 years ago
Water vapor at 5 bar, 320°C enters a turbine operating at steady state with a volumetric flow rate of 1.825 m3/s and expands adi
Monica [59]

Answer: (a).power developed = 776.1 kW

(b). Rate of entropy production = 1.023 kW/K

(c). efficiency = 63%

Explanation:

Let us carry a step by step process to solve this problem;

from the question we have that

P₁ = 5 bar

T₁ = 320°C

where V₁ = 0.5416 m³/Kg, S₁ = 7.5308 KJ/Kg-K and R₁ = 0.3105.6 KJ/Kg

the volumetric flow rate is given as (φ) = 1.825 m³/s

Remember that φ = ṁ V

where ṁ is the mass flowrate, and V is the volume

ṁ = φ/V = 1.825/0.5416 = 3.37 Kg/s

Also given for the Exit state;

P₂ = 1 bar

T₂ = 200°C

where V₂ = 0.5416 m³/Kg, S₂ = 7.5308 KJ/Kg-K and R₂ = 0.3105.6 KJ/Kg

(a). we are asked to determine the power developed in the Kw.

using the Flow energy equation to turbine we have;

ṁ(R₁ + V₁²/2 + gZ₁) + φ = ṁ(R₂ + V₂²/2 + gZ₂₂) + ш

canceling out terms from both steps we have that

ш = 3.37 (3105-2815.3) = 776.1 kW

Therefore the Power output is 776.1 kW

(b). The rate of entropy production in Kw/K.

Rate(en) = ṁ (S₂-S₁) = 3.37 (7.8343 - 7.5308)

Rate(en) = 1.023 kW/K

(c). The percent isentropic  turbine efficiency.

Πt = (R₁-R₂) / (h₁ - h₂s)

Πt = (3105.6 - 2875.3) / (3105.6 - 2740) = 63%

Πt = 63%

cheers i hope this helped!!!!!

4 0
3 years ago
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