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Nutka1998 [239]
4 years ago
7

Depreciation is.... *

Engineering
2 answers:
Ede4ka [16]4 years ago
8 0
Idkkkkkkkkkkkkkkkkk did
qwelly [4]4 years ago
4 0
C) The amount of money(value) a vehicle(or any valuable object) loses with the pass of time.
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Write down the types of the Hydraulic Cylinders?
nirvana33 [79]

Answer:

There are following type of hydraulic cylinders

1.Single acting

2.Double acting

3.Single acting spring loaded

4.Non differential type

5.Ram type

6.Piston type

7.Actuating type

8.Telescopic type

4 0
4 years ago
In the engineering design process, what do engineers do immediately before
gulaghasi [49]

Answer:

A

Hope this helps!

Explanation:

You need to find what the problem is and what can or can not be done to solve that issue/compete the task

5 0
3 years ago
How do we need to prepare for the future?
Paraphin [41]
B. to achieve sustainable development
5 0
3 years ago
Eigth people work in an office.they are paid hourly rates of £12 £15 £15 £14 £13 £14 £13 £13
jok3333 [9.3K]

Answer:

What about it?

Explanation:

8 0
2 years ago
A brittle material is subjected to a tensile stress of 1.65 MPa. If the specific surface energy and modulus of elasticity for th
8090 [49]

Answer:

The maximum length of a surface flaw that is possible without fracture is

2.806 \times 10^{-4} m

Explanation:

The given values are,

σ=1.65 MPa

γs=0.60 J/m2

E= 2.0 GPa

The maximum possible length is calculated as:

\begin{gathered}a=\frac{2 E \gamma_{s}}{\pi \sigma^{2}}=\frac{(2)\left(2 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}\right)(0.60 \mathrm{~N} / \mathrm{m})}{\pi\left(1.65\times 10^{6} \mathrm{~N} / \mathrm{m}^{2}\right)^{2}} \\=2.806 \times 10^{-4} \mathrm{~m}\end{gathered}

The maximum length of a surface flaw that is possible without fracture is

2.806 \times 10^{-4} m

7 0
3 years ago
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