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Katen [24]
3 years ago
11

Pls do this quickly Thank you

Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0

Answer:

288 cu in

Step-by-step explanation:

The Two end pieces

l = 6

w = 4

h = 4

V = l*w*h

V = 6*4*4

V = 96

But there are two end pieces. So the volume for both is 2 * 96 = 192

Middle Piece

L = 8

w = 4

h = 3

Volume = l * w * h

Volume = 8 * 4 * 3

Volume = 96

Total Volume

Total Volume = 96 + 192

Total Volume = 288 Cu in

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According to the graph, which range value corresponds to a domain value of 2?
Mekhanik [1.2K]

Answer:

D

Step-by-step explanation:

Simply put, domain means the x value and range means the y value.

<em><u>The question asks for the corresponding range (y-value) for domain (x-value) of 2. </u></em>

Looking at the graph, x value of 2 corresponds to y value of 4. So the answer is 4.

Correct answer is D

5 0
3 years ago
Read 2 more answers
For the given central angle, determine the distance traveled along the unit circle from the point (1, 0). 360 degrees a. 6.28 un
Alekssandra [29.7K]

Answer:

The length of a 180° arc of a unit circle is π ≈ 3.14 units.

Step-by-step explanation:

Use your knowledge of the circumference of a circle (the length full around) and the fact that there are 360° in the central angle of a full circle. The distance around is proportional to the angle, so an arc of measure 180° will have a length equal to

... (180°/360°) × circumference = (1/2)×circumference

For a unit circle, the circumference is 2π (= π×diameter = 2π×radius). Half that length is π units.

4 0
2 years ago
Find sin (A-B) if sin A = 4/5 with A between 90 and 180 and if cos B = 3/5 with B between 0 and 90
quester [9]

Answer:

sin(A-B) = 24/25

Step-by-step explanation:

The trig identity for the differnce of angles tells you ...

sin(A -B) = sin(A)cos(B) -sin(B)cos(A)

We are given that sin(A) = 4/5 in quadrant II, so cos(A) = -√(1-(4/5)^2) = -3/5.

And we are given that cos(B) = 3/5 in quadrant I, so sin(B) = 4/5.

Then ...

sin(A-B) = (4/5)(3/5) -(4/5)(-3/5) = 12/25 + 12/25 = 24/25

The desired sine is 24/25.

3 0
3 years ago
Which two values of x are roots of the polynomial below?<br> x2-11x + 15
Alex787 [66]

The two values of roots of the polynomial x^{2}-11 x+15 are \frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}

<u>Solution:</u>

Given, polynomial expression is x^{2}-11 x+15

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Given that x^{2}-11 x+15

Here a = 1, b = -11 and c = 15

On substituting the values we get,

x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}

\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}

Hence, the roots of given polynomial are \frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}

6 0
3 years ago
Please help, I have been trying for a while :(<br><br>question on photo​
Zigmanuir [339]

Answer:

\frac{x-22}{(x+2)(x-4)}

Step-by-step explanation:

multiply the numerator/denominator of the first fraction by (x - 4)

multiply the numerator/denominator of the second fraction by (x + 2)

this ensures that the fractions have a common denominator

\frac{4}{x+2} - \frac{3}{x-4}

= \frac{4(x-4)}{(x+2)(x-4)} - \frac{3(x+2)}{(x+2)(x-4)} ← subtract numerators leaving the common denominator

= \frac{4x-16-3x-6}{(x+2)(x-4)}

=\frac{x-22}{(x+2)(x-4)}

4 0
2 years ago
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