When a 9.9 kg object is in free fall, it feels a force of 97.02 N. what is its acceleration?
1 answer:
The acceleration of an object in free fall is
Explanation:
We can solve the problem by using Newton's second law of motion, which states that:
where
F is the net force on an object
m is the mass of the object
a is its acceleration
For the object in this problem, we have:
m = 9.9 kg is its mass
F = 97.02 N is the net force on the object
So, we can rearrange the equation to find its acceleration:
This value is actually known as acceleration of gravity (g), and it is the acceleration that any object in free fall has near the Earth's surface, regardless of its mass.
Learn more about Newton's second law here:
And about free fall:
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Answer:
(a). The magnitude of the total acceleration of the ball is 239.97 m/s².
(b). The angle of the total acceleration relative to the radial direction is 11.0°
Explanation:
Given that,
Radius of the circle = 0.681 m
Angular acceleration = 67.7 rad/s²
Angular speed =18.6 rad/s
We need to calculate the centripetal acceleration of the ball
Using formula of centripetal acceleration
Put the value into the formula
We need to calculate the tangential acceleration of the ball
Using formula of tangential acceleration
Put the value into the formula
(a). We need to calculate the magnitude of the total acceleration of the ball
Using formula of total acceleration
Put the value into the formula
(b). We need to calculate the angle of the total acceleration relative to the radial direction
Using formula of the direction
Put the value into the formula
Hence, (a). The magnitude of the total acceleration of the ball is 239.97 m/s².
(b). The angle of the total acceleration relative to the radial direction is 11.0°