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3 years ago

When a 9.9 kg object is in free fall, it feels a force of 97.02 N. what is its acceleration?

Physics

1 answer:

Free_Kalibri [48]3 years ago

6 0

The acceleration of an object in free fall is $9.8 m/s^2$

Explanation:

We can solve the problem by using Newton's second law of motion, which states that:

$F=ma$

where

F is the net force on an object

m is the mass of the object

a is its acceleration

For the object in this problem, we have:

m = 9.9 kg is its mass

F = 97.02 N is the net force on the object

So, we can rearrange the equation to find its acceleration:

$a=\frac{F}{m}=\frac{97.02}{9.9}=9.8 m/s^2$

This value is actually known as acceleration of gravity (g), and it is the acceleration that any object in free fall has near the Earth's surface, regardless of its mass.

Learn more about Newton's second law here:

brainly.com/question/3820012

And about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

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Read 2 more answers

Someone help please by providing work and answers please :)

Nastasia [14]

First we gotta use an equation of motion:

$d = ut + \frac{1}{2} a {t}^{2}$

Our vertical distance d= 100 m, initial vertical speed u = 0 m/s (because velocity is fully horizontal), and vertical acceleration a = 9.8 m/s2 because of gravity. Let's plug it all in!

$100 = 0 + \frac{1}{2} (9.8) {t}^{2}$

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