TheThe distance they have covered for trip is 219Km.
<h3>What do you mean by uniformly accelereted motion?</h3>
When an object is traveling in a straight line with an increase in velocity at equal intervals of time.
The total time for the trip is
T→ t1+ 22 min = t1+ 0.367 h ,where t1 is the time spent traveling at
V1= 89.5 km/ h .
the distance traveled is ∆x = V1t1=Vavg T
after applying value and calculating it we get
t1= 2.44h for a total time of
t total we get 2.81 h .
∆x =V1T1 = VavgTtotal
∆x = 77×2.81= 219 Km
to learn more about Uniform accelereted motion click here brainly.com/question/12920060
#SPJ4
Answer:
The value is
Explanation:
From the question we are told that
The period of the asteroid is
Generally the average distance of the asteroid from the sun is mathematically represented as
Here M is the mass of the sun with a value
G is the gravitational constant with value
=>
Generally
So
=>
=>
Q out = Q in
Q mix = Q water
mcΔt sand + mcΔt water = mcΔt water
30.2 x 2.01 x (29.3-12.1) + 87.7 x 4.19 x (29.3-12.1)=m x 4.19 x (85.8-29.3)
1044.07+6320.36=m x 236.74
m = 31.11 g
Answer:
a. I = -3mv₀/2 b. F = -3mv₀/2t
Explanation:
a. Use the impulse-momentum to write an equation for the system which is the cart only.
We know Impulse , I = Δp where Δp = change in momentum.
Now, Δp = m(v - u) where m = mass of cart, u = initial velocity of cart = v₀ and v = rebound velocity of cart = -v₀/2 (negative since it moves in the opposite direction to u)
So, I = Δp = m(v - u)
Substituting the values of the variables into the equation, we have
I = m(-v₀/2 - v₀) = -3mv₀/2
So, I = -3mv₀/2
b. If the time during which the bumper exerts a force on the cart is t, write an expression for the force F exerted on the cart in terms of the given variables.
We know impulse I = Ft where F = force exerted on the cart and t = time force acts
Also, I = -3mv₀/2
So, Ft = -3mv₀/2
F = -3mv₀/2t