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alexdok [17]
3 years ago
13

If the recessive allele for an x-linked recessive disease in humans has a frequency of 0.02 in the population, what proportion o

f individuals in the population will have the disease? assume that the population is 50 : 50 male:female.
Biology
1 answer:
juin [17]3 years ago
5 0

<span>To have the disease, males need only one copy of the affected X.</span>

So, the frequency of affected males will be the frequency of the disease allele = 0.02

Females must inherit two copies and be homozygotes, so the frequency of affected females will be the double of frequency of the disease allele = (0.02)

Since the ratio between female and male is 50:50 that is half of the population is male and half female

<span>Then the overall frequency of the disease will be,</span>

(0.5) (0.02) + (0.5) (0.0004) = 0.01 + 0.0002

<span>Thus, the frequency of affected individuals in this population is <span>0.0102.</span></span>

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