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lidiya [134]
3 years ago
7

You push a coin across a table. The coin stops. How does this motion relate to balanced and unbalanced forces?

Physics
1 answer:
Snezhnost [94]3 years ago
7 0
If you are pushing the coin across the table at a constant rate, the friction of the table and the horizontal force of your hand pushing are equal, and the coin itself moves at a constant rate. If you push a coin and let it go, there is no horizontal force keeping the coin going. Friction slows the coin to a stop. In both cases, the gravitational downward pull of Earth is equally but oppositely resisted by the upward push of table on the coin.
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Explanation:

The expression from electrostatic force is as follows;

F=\frac{kq_{1}q_{1}}{r^{2} }

Here, F is the electrostatic force, k is constant, r is the distance between the charges and q_{1},q_{1} are the charges.

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Therefore, the true statements from the given options are as follows;

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