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3 years ago

Which is the dependent variable?

Physics

2 answers:

Bess [88]3 years ago

5 0

Answer:

Number of stars

Explanation:

The given figure shows a graph between the number of stars on the y-axis and constellations on the x-axis. The independent variable is placed on the x-axis and dependent variable on the y-axis. Dependent variable is the one whose value changes when the independent variable is changed. As the constellations vary, the number of stars vary. Thus, number of stars is dependent variable.

zmey [24]3 years ago

4 0

Number of Stars ( Brainliest) if you dont care :)

You might be interested in

Find the components of vtot along the x and y axes in Figure 3.25, where = 23.0° and vtot = 7.56 m/s.

Romashka [77]

The component of the total velocity in the x - direction is 6.96 m/s.

The component of the total velocity in the y - direction is 2.95 m/s.

<h3>Component of the velocity in x direction </h3>

The component of the total velocity in the x - direction is calculated as follows;

v(x) = vtot cosθ

where;

vtot is total velocity
v(x) is velocity in x direction

v(x) = 7.56 x cos(23)

v(x) = 6.96 m/s

<h3>Component of the velocity in y - direction</h3>

v(y) = vtot sinθ

v(y) = 7.56 x sin(23)

v(y) = 2.95 m/s

Learn more about component velocity here: brainly.com/question/24681896

#SPJ1

7 0

2 years ago

A river has a steady speed 0.500 m/s. A student swims upstream a distance of1.00 km and swims back to the starting point. a) If

Ivahew [28]

Answer:

a) 33.6 min

b) 13.9 min

c) Intuitively, it takes longer to complete the trip when there is current because, the swimmer spends much more time swimming at the net low speed (0.7 m/s) than the time he spends swimming at higher net speed (1.7 m/s).

Explanation:

The problem deals with relative velocities.

Call Vr the speed of the river, which is equal to 0.500 m/s
Call Vs the speed of the student in still water, which is equal to 1.20 m/s
You know that when the student swims upstream, Vr and Vs are opposed and the net speed will be Vs - Vr
And when the student swims downstream, Vr adds to Vs and the net speed will be Vs + Vr.

Now, you can state the equations for each section:

distance = speed × time
upstream: distance = (Vs - Vr) × t₁ = 1,000 m
downstream: distance = (Vs + Vr) × t₂ = 1,000 m

Part a). To state the time, you substitute the known values of Vr and Vs and clear for the time in each equation:

(Vs - Vr) × t₁ = 1,000 m
(1.20 m/s - 0.500 m/s) t₁ = 1,000 m⇒ t₁ = 1,000 m / 0.70 m/s ≈ 1429 s
(1.20 m/s + 0.500 m/s) t₂ = 1,000 m ⇒ t₂ = 1,000 m / 1.7 m/s ≈ 588 s
total time = t₁ + t₂ = 1429s + 588s = 2,017s
Convert to minutes: 2,0147 s ₓ 1 min / 60s ≈ 33.6 min

Part b) In this part you assume that the complete trip is made at the velocity Vs = 1.20 m/s

time = distance / speed = 1,000 m / 1.20 m/s ≈ 833 s ≈ 13.9 min

Part c) Intuitively, it takes longer to complete the trip when there is current because the swimmer spends more time swimming at the net speed of 0.7 m/s than the time than he spends swimming at the net speed of 1.7 m/s.

6 0

4 years ago

A low C (f = 65Hz) is sounded on a piano. If the length of the piano wire is 2.0 m and its mass density is 5.0 g/m2, determine t

Pie

Answer:

338N

Explanation:

Use the formula $f=\frac{\sqrt{\frac{T}{\frac{M}{L}} } }{2L}$