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Sati [7]
2 years ago
5

Ahh ahhh ahhh ahhh ahhh ahhh ahhh ahhh ahhh ahha aggg agg

Physics
2 answers:
krek1111 [17]2 years ago
6 0
Agreeable. you have good points there.
timama [110]2 years ago
4 0

shhhh hahahaha ahhhhhhhh ahhhh

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Break the circuit and apace a meter actually within the circuit.
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If X be a vector 3 X represents  3 added to X  3 times of X  the ratio of X and 3  None
jolli1 [7]

Answer:

The correct option is;

3 times of X

Explanation:

The algebraic properties of a vector are;

Multiplicative identity for real numbers 1

1P = P for each P

Scalar associative property = r(sP) = (rs)P

Scalar distributive property (r + s)P = rP + sP

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Additive inverse of a vector such that a vector P has an inverse -P such that we have;

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3 years ago
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anastassius [24]

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6 0
3 years ago
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The roller-coaster car shown in fig. 6-41 (h1 = 45 m, h2 = 16 m, h3 = 26 m), is dragged up to point 1 where it is released from
kirill [66]

There are many ways to solve this but I prefer to use the energy method. Calculate the potential energy using the point then from Potential Energy convert to Kinetic Energy at each points.

PE = KE

From the given points (h1 = 45, h2 = 16, h<span>3  </span>= 26)

Let’s use the formula: 

v2= sqrt[2*Gravity*h1]  where the gravity is equal to 9.81m/s2

v3= sqrt[2*Gravity*(h1 - h3 )] where the gravity is equal to 9.81m/s2

v4= sqrt[2*Gravity*(h1 – h2)] where the gravity is equal to 9.81m/s2

Solve for v2

v2= sqrt[2*Gravity*h1]      

    = √2*9.81m/s2*45m

v2= 29.71m/s

v3= sqrt[2*Gravity*(h1 - h3 )   

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    =√2*9.81m/s2*19 

v3=19.31m/s

v4= sqrt[2*Gravity*(h1 – h2)]        

    =√2*9.81m/s2*(45-16)

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v4=23.85m/s

7 0
3 years ago
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