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Sati [7]
3 years ago
5

Ahh ahhh ahhh ahhh ahhh ahhh ahhh ahhh ahhh ahha aggg agg

Physics
2 answers:
krek1111 [17]3 years ago
6 0
Agreeable. you have good points there.
timama [110]3 years ago
4 0

shhhh hahahaha ahhhhhhhh ahhhh

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Pete Zaria works on weekends at Barnaby's Pizza Parlor. His primary responsibility is to fill drink orders for customers. He fil
laila [671]

Answer:

W_n_e_t=7.648512 \approx 7.6J

K.E=0.8J

v=0.7844645406 \approx 0.78m/s

Explanation:

From the question we are told that

Mass of pitcher   M= 2.6kg

Force on pitcher f=8.8N

Distance traveled 48cm=>0.48m

Coefficient of friction \mu=0.28

a)Generally frictional force is mathematically given by

F=\mu N

F=0.28*2.6*9.8

F=7.1344N

Generally work done on the pitcher is mathematically given as

W_n_e_t=W_f+W_F

W_f=8.8*0.48=>4.224N\\W_F=7.1344*0.48=>3.424512N

W_n_e_t=4.224-3.424512

W_n_e_t=0.799488\approx 0.8J

b)Generally K.E can be given mathematically as

K.E= W_n_e_t

Therefore

K.E=0.8J

c)Generally the equation for kinetic energy is mathematically represented by

K.E=1/2mv^2

0.8=1/2mv^2

Velocity as subject

v=\sqrt{\frac{K.E*2}{m} }

v=\sqrt{\frac{0.8*2}{2.6} }

v=0.7844645406 \approx 0.78m/s

6 0
3 years ago
At locations A and B, the electric potential has the values VA = 1.83 V and VB = 5.17 V, respectively. A proton released from re
densk [106]

Answer:

a. It starts at point B.

vp = 2.53*10⁴ m/s

a. it starts at point A.

ve= 1.08*10⁶ m/s

Explanation:

a)  As the proton is a positive charge, when released from rest, it will be accelerated due to the potential difference, from the higher potential to the lower one, so it is at the point B when released.

Once released, as the total energy must be conserved, the increase in kinetic energy must be equal (in magnitude) to the change in the electric potential energy, as follows:

ΔK + ΔUe = 0 ⇒ ΔK = -ΔUe =- (e*ΔV)

⇒ -( e* (VA-VB) ) = \frac{1}{2}*mp*v^{2}

where e= elementary charge= 1.6*10⁻¹⁹ C,  VA = 1.83 V, VB= 5.17V, and mp= mass of proton = 1.67*10⁻²⁷ kg.

Replacing by these values, and solving for v, we have:

v = \sqrt{\frac{2*1.6e-19C*3.34 V}{1.67e-27kg} } = 2.53e4 m/s

⇒ vp = 2.53*10⁴ m/s

b) If, instead of a proton, the charge realeased from rest, had been an electron, a few things would change:

First, as the electrons carry negative charges, they move from the lower potentials to the higher ones, which means that it would have started at point A.

Second, as its charge is (-e) the change in electric potential energy had been negative also:

ΔUe = -e*ΔV = -e* (VB-VA)

In order to find the speed of the electron when it is just passing point B, we can apply the conservation of energy principle as for the proton, as follows:

-( (-e)* (VB-VA) ) = \frac{1}{2}*me*v^{2}

where e= elementary charge= 1.6*10⁻¹⁹ C,  VA = 1.83 V, VB= 5.17V, and me= mass of electron = 9.1*10⁻³¹ kg.

Replacing by these values, and solving for v, we have:

v = \sqrt{\frac{2*1.6e-19C*3.34 V}{9.1e-31kg} } = 1.08e6 m/s

⇒ ve = 1.08*10⁶ m/s

4 0
3 years ago
All of the following are true statements regarding line-voltage thermostats and control wiring except a. An electrician's licens
n200080 [17]

Answer:

c. Line - voltage thermostats and controls are not as sensitive as low - voltage thermostats.

Explanation:

Line voltage thermostat is a regulator which senses the temperature and maintains it to keep the desired level of the voltage. The license in required for the electricians to work on the voltage control wirings. There is technical aspects which an electrician must understand before working on the circuits and voltage lines.

4 0
3 years ago
Two double bonds means that the total number of electrons being shared in the molecule is
torisob [31]

One double bond consists 4 electrons, so 2 double bonds means 8 electrons

7 0
3 years ago
this stationary wave is what we call the first harmonic of the first normal mode of the system. in units of l, the length of the
pentagon [3]

First harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.

<h3>First harmonic of a closed pipe</h3>

The first harmonic of a closed pipe is the fundamental frequency of the closed of the closed pipe.

L = λ/4

where;

  • L is the length of the pipe
  • λ is the wavelength of sound

λ = 4L

But, v = F₀λ

v = F₀(4L)

F₀ = v/4L

where;

  • F₀ is the first harmonic
  • v is speed of sound

Thus, first harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.

Learn more about fundamental frequency here:  brainly.com/question/1967686

#SPJ11

<h3 />
6 0
1 year ago
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