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3 years ago

13

El profesor pide a juan que le indique tres magnitudes de su libro de texto y el le contesta; su peso, tamaño y el diseño de la

portada. ¿es correcta su respuesta? En su caso, ¿que no es correcto?

1 answer:

nydimaria [60]3 years ago

6 0

Answer:

Explanation:

Yo creo que el no es correcto y que no es correcto es el diseño de la portada

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If the body's temperature is above 105 °F for a prolonged period, heat stroke

seraphim [82]

Answer:

A

Explanation:

C = (F-32)*5/9 = 73*5/9 = 40.55555

since the answers are spread apart, technically you can just estimate by doing -32

and then /2

since 5/9 is close to 1/2

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3 years ago

How does the loneliest whale relate to physics/waves.

Lelechka [254]

Answer: the loneliest whale relates to the communication that whales give to each other

Explanation: whales have different forms of communication , and the ‘loneliest’ whale can’t get any company by the other whales.

In other words: it may be a new and different way whales communicate, nobody knows much about the loneliest whale. It may be forming a new kind of communication

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3 years ago

which actions most likely cause the domains within a material to lose their alignment and become more randomized

zimovet [89]

answer:

heating the material

placing the material in a magnetic field of opposite polarity

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4 0

3 years ago

Read 2 more answers

The initial volume reading in a graduated cylinder is 30 mL. The mass of an irregular shape of an unknown metal piece is 55.3 g.

Vadim26 [7]

Answer:

7.9 $\frac{gr}{cm^3}$

Explanation:

When we put the metal piece in the liquid (which is in the graduated cylinder), how much it goes up is equal to the volume of the piece we inserted.

So now we know that the volume of that piece of unknown metal is 7mL (which is the same as 7 $cm^3$ ).

Density is $\frac{mass}{volume}$ .

So the density of that piece of metal is $\frac{55.3g}{7cm^3}$

Which leaves us with a final density of 7.9 $\frac{gr}{cm^3}$

6 0

3 years ago

A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on

MAXImum [283]

Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.

Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

$Ec=\frac{1}{2} *m*v^{2}$

where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).

The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:

$W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}$

$W=\frac{1}{2} *m*(v2^{2}-v1^{2})$

In this case:

W=?
m= 2,145 kg
v2= 12 $\frac{m}{s}$

v1= 25 $\frac{m}{s}$

Replacing:

$W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})$

W= -515,872.5 J

<u><em>The work required is -515,872.5 J</em></u>

3 0

3 years ago