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3 years ago

A gas at 400 k is placed in a 4.0 l moveable piston. The gas is cooled to 252 k. What is the new volume of the piston?

Chemistry

1 answer:

katrin [286]3 years ago

6 0

Answer:

2.52L

Explanation:

Given parameters:

T₁ = 400K

V₁ = 4L

T₂ = 252K

unknown

V₂ = ?

Solution:

To solve this problem, we are going to apply charle's law. The law states that the volume of a fixed mass of gas is directly proportional to temperature provided pressure is constant.

Mathematically,

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

Substitute and solve for V₂

$\frac{4}{400} = \frac{V_{2} }{252}$

V₂ = 2.52L

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BH+ClO4- is a salt formed from the base B (Kb = 1.00e-4) and perchloric acid. It dissociates into BH+, a weak acid, and ClO4-, w

Len [333]

Answer:

The pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44

Explanation:

Given: The base dissociation constant: $K_{b}$ = 1 × 10⁻⁴, Concentration of salt: BH⁺ClO₄⁻ = 0.1 M

Also, water dissociation constant: $K_{w}$ = 1 × 10⁻¹⁴

The acid dissociation constant ( $K_{a}$ ) for the weak acid (BH⁺) can be calculated by the equation:

$K_{a}. K_{b} = K_{w}$

$\Rightarrow K_{a} = \frac{K_{w}}{K_{b}}$

$\Rightarrow K_{a} = \frac{1\times 10^{-14}}{1\times 10^{-4}} = 1\times 10^{-10}$

Now, the acid dissociation reaction for the weak acid (BH⁺) and the initial concentration and concentration at equilibrium is given as:

Reaction involved: BH⁺ + H₂O ⇌ B + H₃O+

Initial: 0.1 M x x

Change: -x +x +x

Equilibrium: 0.1 - x x x

The acid dissociation constant: $K_{a} = \frac{\left [B \right ] \left [H_{3}O^{+}\right ]}{\left [BH^{+} \right ]} = \frac{(x)(x)}{(0.1 - x)} = \frac{x^{2}}{0.1 - x}$

$\Rightarrow K_{a} = \frac{x^{2}}{0.1 - x}$

$\Rightarrow 1\times 10^{-10} = \frac{x^{2}}{0.1 - x}$

$As, x$

$\Rightarrow 0.1 - x = 0.1$

$\therefore 1\times 10^{-10} = \frac{x^{2}}{0.1 }$

$\Rightarrow x^{2} = (1\times 10^{-10})\times 0.1 = 1\times 10^{-11}$

$\Rightarrow x = \sqrt{1\times 10^{-11}} = 3.16 \times 10^{-6}$

Therefore, the concentration of hydrogen ion: x = 3.6 × 10⁻⁶ M

Now, pH = - ㏒ [H⁺] = - ㏒ (3.6 × 10⁻⁶ M) = 5.44

Therefore, the pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44

5 0

3 years ago

A sample of hydrogen gas has an initial pressure of 2.86 atm and an initial volume of 8472 mL If the volume of the

Oliga [24]

<h3>Answer:</h3>

Gas law : Boyle's law

New pressure: 66.24 atm

<h3>Explanation:</h3>

Concept tested: Gas laws (Boyle's law)

We are given,

Initial pressure, P₁ = 2.86 atm
Initial volume, V₁ = 8472 mL
New volume, V₂ IS 365.8 mL

We need to determine the new pressure, P₂

According to Boyle's law , the volume of a fixed mass of a gas and the pressure are inversely proportional at constant temperature.

That is, $P\alpha \frac{1}{V}$
This means , PV = k (constant)
Therefore; P₁V₁ = P₂V₂

Rearranging the formula, we can get the new pressure, P₂

P₂ = P₁V₁ ÷ V₂

= (2.86 atm × 8472 mL) ÷ 365.8 mL

= 66.24 atm

Therefore, the new pressure is 66.24 atm

5 0

3 years ago

You have 500,000 atoms of a radioactive substance. After 2 half-lives have past, how many atoms remain?

Aleonysh [2.5K]

Answer:

125000

Explanation:

Because it is halved and halved again.

3 0

2 years ago

Read 2 more answers

How many moles are in 35.0 grams of H₂O?

Nikitich [7]

1.94 moles

I did 35/18.02 because 18.02 is the molar mass of water

3 0

3 years ago

This question is about metal oxides. When sodium is heated in oxygen, sodium oxide is produced.

vodomira [7]

Answer:

This is very easy Cuz We have 2Na2O We have O2 so thats molecule of Oxygen and its same on product We need to balance Na on start We have 1 on product We have 2 so Just put 2 at start....

Explanation:

Sorry for bad english not my first language :(

2Na+O2-->2Na20

5 0

3 years ago