Question

A gas at 400 k is placed in a 4.0 l moveable piston. The gas is cooled to 252 k. What is the new volume of the piston?

Answer 1

Answer:

2.52L

       

Explanation:

Given parameters:

T₁  = 400K

V₁  = 4L

T₂ = 252K

unknown

V₂ = ?

Solution:

To solve this problem, we are going to apply charle's law. The law states that the volume of a fixed mass of gas is directly proportional to temperature provided pressure is constant.

Mathematically,

               $\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

Substitute and solve for V₂

           $\frac{4}{400} = \frac{V_{2} }{252}$

        V₂ = 2.52L