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Tju [1.3M]
3 years ago
6

Increasing the temperature of a solution will slow down the dissolving/dissolution of the solute.

Chemistry
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

False

Explanation:

It will actually speed it up

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Which of the is an example of climate???<br> Help pls?
n200080 [17]
The first one, my friend
4 0
3 years ago
Read 2 more answers
A sample has a mass of 1.2 g and a volume of 1.1 cm? What is the density of this sample?
mamaluj [8]

Answer:

Density is a physical quantity, defined as the ratio of body mass to the volume occupied by this body.  The average body density is the ratio of body weight to its volume.

Since the mass in a body can be distributed unevenly, a more adequate model defines the density at each point of the body as a derivative of mass over volume.

Thus, to obtain the density of a sample, its mass must be divided by its volume. Thus, the density of the sample is 1.2 / 1.1, that is, 1.09 g/cm3.

7 0
3 years ago
Gases, as opposed to solids, do not have definite volumes. If we decrease the volume of a gas in a closed container, the result
mafiozo [28]
I would believe that the answer is B
6 0
3 years ago
Question 2
Naddika [18.5K]

Answer:

38.4 atm

Explanation:

Data obtained from the question include:

V1 (initial volume) = 3200 L

P1 (initial pressure) = 3.00 atm

V2 (final volume) = 250.0 L

P2 (final pressure) = ?

Using Boyle's law equation P1V1 = P2V2, the final pressure can be obtained as follow:

P1V1 = P2V2

3 x 3200 = P2 x 250

Divide both side by 250

P2 = 3 x 3200/250

P2 = 38.4 atm

Therefore, the pressure of the gas if ethylene is supplied by a 250.0 L tank is 38.4 atm

5 0
4 years ago
A gas is collected at 20.0 °C and 725.0 mm Hg. When the temperature is
krek1111 [17]

Answer:

676mmHg

Explanation:

Using the formula;

P1/T1 = P2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 725.0mmHg

P2 = ?

T1 = 20°C = 20 + 273 = 293K

T2 = 0°C = 0 + 273 = 273K

Using P1/T1 = P2/T2

725/293 = P2/273

Cross multiply

725 × 273 = 293 × P2

197925 = 293P2

P2 = 197925 ÷ 293

P2 = 676mmHg.

The resulting pressure is 676mmHg

3 0
3 years ago
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