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Tju [1.3M]
3 years ago
6

Increasing the temperature of a solution will slow down the dissolving/dissolution of the solute.

Chemistry
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

False

Explanation:

It will actually speed it up

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3. From the following formula, calculate the quantities required to make 5 lb o hydrophilic ointment. Methylparaben 0.25 g Propy
adell [148]

The given question is incomplete. The complete question is as follows.

From the following formula, calculate the quantities required for each of the following ingredients to make 5 lb. (avoir) of hydrophilic ointment. All values to be in g, do not include units in your submitted answer; use no more than 3 decimal places. Convert using 1 lb = 454 g. Note: all values done by mass, including the water, so this is not a q.s situation (volume is irrelevant).

Methylparaben 0.25 g

Propylparaben 0.15 g

Sodium Lauryl Sulfate 10 g

Propylene Glycol 120 g

Stearyl Alcohol 240 g

White Petrolatum 250 g

Purified Water, to make 1000 g

Explanation:

For the given quantities, the sum is 620.4 g. Now, amount of purified water (to make 1000 g of ointment)  is as follows.

             1000 g - 620.4 g

           = 379.6 g

Now, to make 5 lb we will calculate the quantities as follows.

Formula weight = 1000 g

Therefore, desired quantity is as follows.

             5 lb = 5 x 454 g

                     = 2270 g

Hence, this means the factor is  calculated as follows.

       \frac{2270 g}{1000 g}

            = 2.27

Now, we will calculate the quantity of each ingredient using factor 2.27 as follows.

  • Methylparaben = 0.25 g x 2.27 = 0.5675 g
  • Propylparaben = 0.15 g x 2.27 = 0.3405 g
  • Sodium Lauryl Sulfate = 10 g x 2.27 = 22.7 g
  • Propylene Glycol = 120 g x 2.27 = 272.4 g
  • Stearyl Alcohol = 240 g x 2.27 = 544.8 g
  • White Petrolatum = 250 g x 2.27 = 567.5 g
  • Purified Water = 379.6 g x 2.27 = 861.692 g
7 0
3 years ago
Cells are the __________ Life unties on this planet
Paraphin [41]

Answer:

BASIC

Explanation:

brainliest :))

3 0
3 years ago
Read 2 more answers
What current (in a) is required to plate out 1. 22 g of nickel from a solution of ni2 in 0. 50 hour?
Mashcka [7]

The current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.

<h3>What is current?</h3>

The current is given as the product of the charge with time. In the electrochemical analysis of the nickel, there will be a reduction of the nickel ion to nickel. The formation is given as:

\rm Ni^{2+}+2e^-\;\rightleftharpoons Ni

There is the deposition of 1 mole of Ni with 2 electrons transfer. The transfer of charge for 1 mole that is 58.7 grams Nickel is:

\rm 58.7\;g=2\;\times\;96487\;C\\58.7\;g=192974\;C

The mass of Ni to be deposited is 1.22 grams. The charge required is given as:

\rm 58.7\;grams\;Ni=192974\;C\\\\1.22\;grams\;Ni=\dfrac{192974}{58.7}\;\times\;1.22\;C\\\\1.22\;grams\;Ni=4010.7\;C

The current required to transfer 4010.7 C of charge in 1800 seconds is given as:

\rm Charge=Current\;\times\;Time\\4010.7\;C=Current\;\times\;1800\;sec\\Current=2.23\;A

Thus, the current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.

Learn more about current, here:

brainly.com/question/23063355

#SPJ4

7 0
2 years ago
A graduated cylinder has 100 mL of water in it. A rock is then placed in the cylinder
gulaghasi [49]

Answer:

105-100=5 ,

{5cm}^{3 }

8 0
3 years ago
A textbook measures 250 mm long, 225 mm wide and 50 mm thick. What is the volume of this book in mm3? What is the volume of this
Dvinal [7]

Answer:

2.81 × 10⁶ mm³

2.81 × 10⁻³ m³

Explanation:

Step 1: Given data

Length (l): 250 mm

Width (w): 225 mm

Thickness (t): 50 mm

Step 2: Calculate the volume of the textbook

The book is a cuboid so we can find its volume (V) using the following expression.

V = l × w × t = 250 mm × 225 mm × 50 mm = 2.81 × 10⁶ mm³

Step 3: Convert the volume to cubic meters

We will use the relationship 1 m³ = 10⁹ mm³.

2.81 × 10⁶ mm³ × 1 m³ / 10⁹ mm³ = 2.81 × 10⁻³ m³

6 0
3 years ago
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