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harina [27]
3 years ago
12

The Earth's average density a. can be deduced from its volume and gravitational pull. b. is the same as rocks on the surface. c.

is greater than that of an iron meteorite. d. is about the same as the core.
Physics
1 answer:
tester [92]3 years ago
3 0

Answer:

option A

Explanation:

Earth density can be deduced with the help of gravitational pull and the volume.

gravitational pull of the earth is equal to= \dfrac{GM}{R^2}........(1)

We know, the volume of the earth, with the help of that we can calculate radius of the earth.

We know gravitational pull on earth = 9.8 m/s²

From equation (1) we can calculate the mass.

So, Density = mass/ Volume.

From the above expression we can calculate the density of earth.

Hence, the correct answer is option A

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What is the main difference between macroscopic kinetic energy in a motion and microscopic kinetic energy of individual molecule
labwork [276]

Answer:

Explained

Explanation:

1.The macroscopic form of kinetic energy is organized whereas the microscopic kinetic energy disorganized form of energy.

2.Observing macroscopic kinetic energy is easier than the microscopic energy.

3. All macroscopic kinetic energy can be converted to useful work whereas microscopic kinetic energy can not be.

4. Macroscopic kinetic energy is possessed  by moving objects whereas microscopic objects possessed by the virtue of motion, rotation, vibrations of atoms in substance.

Wind energy is macroscopic energy as it can be harnessed to produce electricity and perform some useful work. And discussed above useful work can only be performed using macroscopic kinetic energy.

8 0
3 years ago
A 40-W lightbulb is 1.9 m from a screen. What is the intensity of light incident on the screen? Assume that a lightbulb emits ra
valentinak56 [21]

Answer:

INTNESITY = 0.88W/m^{2}

Explanation:

given data:

power P =  40W

Distance of light bulb from screen is  R  = 1.9 m

The light intensity considered as  the light energy falling on the surface per unit area per unit time

Intensity of light can be determined by using following formula

intesnity = \frac{P} {4\pi R^{2}}

intesnity = \frac{40} {4\pi *1.9^{2}}

INTNESITY = 0.88W/m^{2}

8 0
3 years ago
I NEED THIS FAST!
Romashka [77]
The variable you can change in an experiment is ( B ) A dependent variable
6 0
3 years ago
Read 2 more answers
A rocket travels at a speed of 14,000 m/s. What is the distance travelled by the rocket in 150s?
kati45 [8]

1) The distance travelled by the rocket can be found by using the basic relationship between speed (v), time (t) and distance (S):

v=\frac{S}{t}

Rearranging the equation, we can write

S=vt

In this problem, v=14000 m/s and t=150 s, so the distance travelled by the rocket is

S=vt=(14000 m/s)(150 s)=2.1 \cdot 10^6 m


2) We can solve the second part of the problem by using the same formula we used previously. This time, t=300 s, so we have:

S=vt=(14000 m/s)(300 s)=4.2 \cdot 10^6 m/s

5 0
4 years ago
a load of 400 Newton is lifted by a first class lever in which the load is at the distance of 20 cm and the effort is at the dis
Len [333]

Answer:

  1. solution,
  2. Given
  3. load =400N
  4. ld=0.2m
  5. ed=0.6m
  6. effort =150N

Explanation:

efficiency =output work/input work ×100%

l×ld/e×ed×100%

400×0.2/150×0.6×100%

80/90×100%

88.89%ans

7 0
3 years ago
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