Its called a spiral galaxy... our galaxy is an spiral galaxy, case its apart of the milky way making it spiral
I have a strange hunch that there's some more material or previous work
that goes along with this question, which you haven't included here.
I can't easily find the dates of Mercury's extremes, but here's some of the
other data you're looking for:
Distance at Aphelion (point in it's orbit that's farthest from the sun):
<span><span><span><span><span>69,816,900 km
0. 466 697 AU</span>
</span>
</span>
</span>
<span>
Distance at Perihelion
(</span></span><span>point in it's orbit that's closest to the sun):</span>
<span><span><span><span>46,001,200 km
0.307 499 AU</span> </span>
Perihelion and aphelion are always directly opposite each other in
the orbit, so the time between them is 1/2 of the orbital period.
</span><span>Mercury's Orbital period = <span><span>87.9691 Earth days</span></span></span></span>
1/2 (50%) of that is 43.9845 Earth days
The average of the aphelion and perihelion distances is
1/2 ( 69,816,900 + 46,001,200 ) = 57,909,050 km
or
1/2 ( 0.466697 + 0.307499) = 0.387 098 AU
This also happens to be 1/2 of the major axis of the elliptical orbit.
Force of friction is applied,
The initial velocity of the ball is 8.2 m/s
Explanation:
The motion of the ball is a projectile motion, which consists of two separate motions:
- A uniform motion along the horizontal direction, at constant velocity
- A uniformly accelerated motion along the vertical direction, with constant acceleration (
, acceleration of gravity)
The range of a projectile can be derived by the equation of motions along the two directions, and it is found to be:
where
v is the initial velocity of the projectile
is the angle of projection
g is the acceleration of gravity
For the ball in this problem, we have
d = 6 m is the range
Solving for v, we find the initial velocity:
Learn more about projectile motion:
brainly.com/question/8751410
#LearnwithBrainly
