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ahrayia [7]
3 years ago
10

The work-energy theorem states that the work done on an object is equal to a change in which quantity?

Chemistry
1 answer:
djverab [1.8K]3 years ago
7 0

Answer :

A.) Kinetic energy

Explanation:

When work is either added to or taken away from a system, it forces the <u>kinetic energy</u> to change.

The work-energy theorem states : change in <u>kinetic energy</u> of an object is <u>equal</u> to the <u>work done on the object</u>

[ I took the quiz already on Edgenuity and received 100% ]

Hope this helped ! :)

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adoni [48]

Answer:

Overall reaction equation;

2NO(g) +Cl2(g) -----> 2NOCl (g)

Explanation:

Given

1) NO(g) + Cl2(g) → NOCl2(g)

2) NOCl2(g) + NO(g) → 2NOCl(g)

Overall reaction equation;

2NO(g) +Cl2(g) -----> 2NOCl (g)

k1= [NOCl2]

k-1= [NO] [Cl2]

k2 = [NOCl2] [NO]

Equilibrium for the first equation (reaction 1)

K= k1/k-1 = [NOCl2]/[NO] [Cl2]

Therefore

[NOCl2] = k1/k-1 [NO] [Cl2]

Rate= k2× k1/k-1 [NO]^2 [Cl2]

Rate = Koverall [NO]^2 [Cl2]

Where Koverall= k1k2/k-1

3 0
4 years ago
What kind of reaction does luminol go through?
vivado [14]

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Explanation: i looked the answer up but your welcomee ❤

7 0
3 years ago
Compounds A and B are colorless gases obtained by combining sulfur with oxygen. Compound A results from combining 6.00 g of sulf
sukhopar [10]

Answer:

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Explanation:

Given that :

Compound A and B are formed from Sulfur + Oxygen.

Compound A :

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Compound B:

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Comparing the ratios :

Compound A:

S : O = 6.00 : 5.99

S/0 = 6.0g S / 5.99g O

Compound B :

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S / O = 8.60g S / 12.88g O

Mass Ratio of A / mass Ratio of B

(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)

(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)

(6 × 12.88) / (5.99 × 8.60)

= 77.28 / 51.514

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4 0
4 years ago
During cellular respiration, plants take in _______ from the air and break down stored _______.
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Answer:

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8 0
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