Answer:
The angular acceleration of the centrifuge is -231.74 rad/s².
Explanation:
Given that,
Angular speed = 3500 rev/min = 366 rad/s
We need to calculate the angular displacement
Using formula of angular displacement
![\theta=2\pi n](https://tex.z-dn.net/?f=%5Ctheta%3D2%5Cpi%20n)
Put the value into the formula
![\theta=2\pi\times46](https://tex.z-dn.net/?f=%5Ctheta%3D2%5Cpi%5Ctimes46)
![\theta=289.02\ rad](https://tex.z-dn.net/?f=%5Ctheta%3D289.02%5C%20rad)
We need to calculate the angular acceleration
Using equation of motion
![\omega_{f}^2=\omega_{i}^2+2\alpha\theta](https://tex.z-dn.net/?f=%5Comega_%7Bf%7D%5E2%3D%5Comega_%7Bi%7D%5E2%2B2%5Calpha%5Ctheta)
![\alpha=\dfrac{\omega_{f}^2-\omega_{i}^2}{2\theta}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B%5Comega_%7Bf%7D%5E2-%5Comega_%7Bi%7D%5E2%7D%7B2%5Ctheta%7D)
![\alpha=\dfrac{0-(366)^2}{2\times289.02}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B0-%28366%29%5E2%7D%7B2%5Ctimes289.02%7D)
![\alpha=-231.74\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%3D-231.74%5C%20rad%2Fs%5E2)
Hence, The angular acceleration of the centrifuge is -231.74 rad/s².
<span>C.) A metalloid is used because it is a semiconductor and can become more conductive when more light shines on it.
Nonmetals do not conduct energy any way and you want the metalloid to be conductive so it can provide you with energy.
</span><span>C.) intermediate conductivity and a high melting point
</span>It conducts electricity fairly well.
Hope this helps.
Answer:
15.71 m/s
Explanation:
We are given;
Time; t = 0.2 s
Radius; r = 0.5 m
The circumference will give us the distance covered.
Formula for circumference is 2πr
Thus; Distance = 2πr = 2 × π × 0.5 = π
Linear speed = distance/time = π/0.2 = 15.71 m/s
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