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jeyben [28]
2 years ago
15

Need help with this science question............

Chemistry
1 answer:
Brums [2.3K]2 years ago
4 0

Answer:

18- H

19- D

20-G

21-A

(i think these are the answers)

Explanation:

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Sodium metal reacts with water to produce hydrogen gas.
Kobotan [32]

Answer: I just took the test. The answer is D! (A single replacement reaction takes place because sodium is more reactive than hydrogen.)

5 0
3 years ago
Read 2 more answers
Mercury can be obtained by reacting mercury(I) sulfide with calcium oxide. How many grams of calcium oxide are needed to produce
OLga [1]
First, 55 g of Hg is 3.65 moles because one mole of Hg has a molar mass of 200.59

Then, the mole ratio of Hg to CaO is 8:4 or 2:1. SO we divide 3.65 by 2 to get 1.82 moles of CaO

This is the same as 102.06 grams because one mole of CaO has a molar mass of 56.0774

Hope this helps!
4 0
3 years ago
What is the E°cell for the cell represented by the combination of the following half-reactions? ClO4–(aq) + 8H+(aq) + 8e– Cl–(aq
Vinvika [58]

Answer:

The E°cell for the cell represented by the combination of the given half-reactions is 0.398 V

Explanation:

Oxide-reduction reactions, also called redox, involve the transfer or transfer of electrons between two or more chemical species. In these reactions two substances interact: the reducing agent and the oxidizing agent.

The gain of electrons is called reduction and the loss of electrons oxidation. That is to say, there is oxidation whenever an atom or group of atoms loses electrons (or increases its positive charges) and in the reduction an atom or group of atoms gains electrons, increasing its negative charges or decreasing the positive ones.

The species that supplies electrons is the reducing agent (that is, it is that species that oxidizes, yielding electrons and increasing its positive charge, or decreasing the negative one causing the reduction of the other species) and the one that gains them is the oxidizing agent ( that is, it is that species that is reduced, capturing electrons and increasing its negative charge, or decreasing its positive charge, causing oxidation of the other species).

This is the type of reaction that occurs in this case.

ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

VO₂⁺(aq) + 2 H⁺(aq) + e⁻ ⇔ VO⁺(aq) + H₂O(l) E° = 0.991 V

In this case both are written as reductions, and their E ° values ​​as well. The species that has the greatest potential for reduction will be the species that will be reduced, that is, it will be the oxidizing agent. In this case, it will be the first half-reaction expressed.  Therefore, to obtain a reaction, the second semi-reaction must be reversed to be an oxidation, maintaining its constant value. Then:

Reduction: ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

Oxidation: VO⁺(aq) + H₂O(l) ⇔ VO₂⁺(aq) + 2 H⁺(aq) + e⁻ E° = 0.991 V

<em>E°cell=Ereduction - Eoxidation</em>

E°cell=1.389 V - 0.991 V

<em>E°cell=0.398 V</em>

Then <u><em>the E°cell for the cell represented by the combination of the given half-reactions is 0.398 V.</em></u>

Another way of thinking is that, by inverting the second semi-reaction to be an oxidation, the value of E ° is reversed in the sign, unlike the previous case in which it was constant. Then:

Reduction: ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

Oxidation: VO⁺(aq) + H₂O(l) ⇔ VO₂⁺(aq) + 2 H⁺(aq) + e⁻ E° = -0.991 V

In this case:

E°cell=Ereduction + Eoxidation=

E°cell=1.389 V + (-0.991 V)=1.389 V-0.991 V

<em>E°cell=0.398 V</em>

Note that the result obtained is the same. This indicates that either of the two ways proposed is correct, and you will use the one that is most comfortable for you.

4 0
3 years ago
What happens when a compound is formed between the two substance
fiasKO [112]

Answer: i would say the first one

Explanation:

6 0
3 years ago
I will give Brainlyiest! I just need this ASAP :)
serg [7]
Equation of reaction:

                                        2 Na + Cl₂   →   2 NaCl

Oxidation States:
                                         L.H.S                    R.H.S
                      O.N of Na  =  0                           +1  =  O.N of Na in NaCl
                       O.N of Cl  =  0                            -1  =  O.N of Cl in NaCl

Oxidation Reaction:
               In this reaction O.S of Na is changing from 0 to +1 state, means it has oxidized with a loss of 1 electron,

                                             Na   →   Na⁺  +   e⁻

Reduction Reaction:
                In this reaction O.S of Cl is changing from 0 to -1 state, means it has reduced with a gain of 1 electron per atom,

                                            Cl₂  +   2e⁻   →   2Cl⁻

Oxidizing Agent:
                        In this reaction Cl is oxidizing agent as it has gain electron from sodium and has oxidized Na to Na⁺.

Reducing Agent:
                          In this reaction Na is reducing agent as it has given electron to chlorine and has reduced Cl to Cl⁻.
5 0
3 years ago
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