To solve this problem it is necessary to apply the concepts related to pressure as a unit that measures the force applied in a specific area as well as pressure as a measurement of the density of the liquid to which it is subjected, its depth and the respective gravity.
The two definitions of pressure can be enclosed under the following equations
Where
F= Force
A = Area
Where,
Density
g = Gravity
h = Height
Our values are given as,
If we make a comparison between the lid and the tube, the diameter of the tube becomes negligible.
Matching the two previous expressions we have to
Re-arrange to find h
Therefore the height of water in the tube is 7.9cm
Answer:
1.Reduced pedal travel
2. Firmer pedal feel
Explanation:
A power brake booster is defined as a device that reduces the amount of force that it takes to apply hydraulic brakes. Power brake boosters harness manifold vacuum to accomplish this. Brake booster multiply force on the pedal to the master cylinder
Vacuum booster works by pulling the air out of the booster chamber with a pump creating a low pressure system inside. As soon as the driver steps on the brake pedal, atmospheric pressure is pushed into the booster by the input rod booster.
The advantage of cargos hydraulic brake booster over conventional vacuum booster is reduced pedal travel and firmer pedal feel
Potential energy due to gravity = Ep = mgh [symbols have their usual meaning
Evidently, HALVING the mass will make Ep , HALF its previous value. So, It will be halved.
Answer:
36 Ω
Explanation:
Since the 3 resistors are connected in parallel.
The combined resistance of the resistor is
1/Rc = 1/R + 1/R + 1/R ...................... Equation 1
Where Rc = combined resistance of the three resistor, R1 = Resistance of each of the resistor
Rc = R/3 ....................... Equation 2
The formula of power is given as
P = V²/Rc
Rc = V²/P ................ Equation 3
Where V = Voltage, R = Combined Resistance, P = power.
Given: V = 48 V, 192 W.
Substitute into equation 3
Rc = 48²/192
Rc = 12 Ω
From equation 2
Rc = R/3
R = 3Rc
Where Rc = 12 Ω
R = 3×12
R = 36 Ω
Hence the resistance on each resistor = 36 Ω