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amm1812
3 years ago
14

A sinusoidal wave has the following wave function: y(x,t) = (2.5 m) sin((3.0 m ) x - (24 s-')t + Tt/2] What is the frequency of

this wave? (a) 0.48 Hz, (b) 3.0 Hz, (c) 3.8 Hz, (d) 12 Hz, (e) 24 Hz.
Physics
1 answer:
vladimir1956 [14]3 years ago
8 0

Answer:

Frequency of the wave is 3.8 hertz.

Explanation:

It is given that, the sinusoidal wave has following wave equation as :

y(x,t)=(2.5\ m)sin[(3\ m^{-1})x-(24\ s^{-1})t+\pi/2]

The general equation for the sinusoidal wave is :

y=A\ sin(kx-\omega t+\phi)

Where

A is the amplitude

k is the constant

\omega is the angular frequency

\phi is the phase difference

Since, \omega=24\ s^{-1}

2\pi f=24

f=\dfrac{24}{2\pi}=3.81\ Hz

or

f = 3.8 Hz

So, the frequency of the wave is 3.8 hertz. Hence, this is the required solution.

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