Question

A hockey puck with mass 0.200 kg traveling east at 10.0 m/s strikes a puck with a mass of .250 kg heading north at 20 m/s and stick together. What is the magnitude of the .250 kg puck's velocity after the collision?

Answer 1

Answer:

4.44 i + 11.11 j , 11.96 m/s

Explanation:

m1 = 0.2 kg, v1 = 10 m/s along X axis, v1 = 10 i

m2 = 0.25 kg, v2 = 20 m/s along north, v2 = 20 j

After collision they stick together and let they move with velocity v.

Use the conservation of momentum

m1 x v1 + m2 x v2 = (m1 + m2) x v

0.2 x (10 i) + 0.25 x (20 j) = (0.2 + 0.25) x v

2i + 5j = 0.45 v

v = 4.44 i + 11.11 j

magnitude of velocity = $\sqrt{(4.44)^{2}+(11.11)^{2}}$ = 11.96 m/s

Thus, the velocity of 0.250 kg hockey puck is 4.44 i + 11.11 j  metre per second and the magnitude of velocity is 11.96 m/s.