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slega [8]
3 years ago
15

NEED HELP ASAPPPPPPP!

Physics
2 answers:
AlekseyPX3 years ago
3 0

Answer:

Changeable. Answer is c

Explanation:

Andrei [34K]3 years ago
3 0
The answer is Changeable
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A fisherman moves from one end of a boat to another
Naily [24]

Answer:

That isnt a question so no one will know the answer to what you are talking about. I suggest adding a sceenshot or picture of the question.

5 0
2 years ago
Eugene describes the physical property of a material as “sweet and floral.” What physical property of the material is Eugene mos
shusha [124]

The correct answer would be odor. Because it's sweet.  Boiling shape and hardness have nothing to do with sweet and floral :)

7 0
3 years ago
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Which equation represents the law of conservation of energy in a closed system?
Irina-Kira [14]

Answer:

KE + PE = KE + PE

Explanation:

In a closed system, the mechanical energy of the system is constant.

Mechanical energy is given by the sum of kinetic energy and potential energy; mathematically:

U = KE + PE

where

KE is the kinetic energy

PE is the potential energy

This means that if we consider two situations, one at the beginning and one at the end, the value of U will not change if the system is closed; this means that the sum KE + PE will remain the same, so we can write:

KE + PE = KE + PE

7 0
3 years ago
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Help on matching please, struggling on it. Even just 1 or 2 would help
n200080 [17]

Answer:

7. free fall -- h. 9.8m/s^2

3. Velocity -- x. 60 km/hr west

6. Acceleration -- d. change in velocity/time

8. Centrifugal --  s. towards the centre

13. Work done --w. Force * displacement

5. Uniform circular motion --j. spin cycle in washer

18. Power -- r. kW an hour

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hope this helps

6 0
2 years ago
Chameleons catch insects with their tongues, which they can rapidly extend to great lengths. In a typical strike, the chameleon’
Yuki888 [10]

Answer:

0.2 m

Explanation:

PHASE 1

First, we calculate the distance the tongue moved in the first 20 ms (0.02 secs). We use one of Newton's equations of linear motion:

s = ut + \frac{1}{2}at^2

where u = initial velocity = 0 m/s

a = acceleration = 250 m/s^2

t = time = 0.02 s

Therefore:

s = 0 + \frac{1}{2} * 250 * (0.02)^2\\\\\\s = 0.05 m

PHASE 2

Then, for the next 30 ms (0.03 secs), we use the formula:

distance = speed * time

This speed is the same as the final velocity of the tongue after the first 20 ms.

This can be obtained by using the formula:

v = u + at\\\\=> v = 0 + (250 * 0.02)\\\\\\v = 5 m/s

Therefore:

distance = 5 * 0.03 = 0.15 m

Therefore, the total distance moved by the tongue in the 50 ms interval is:

0.05 + 0.15 = 0.2 m

8 0
3 years ago
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