Explanation:
It is given that, Onur drops a basketball from a height of 10 m on Mars, where the acceleration due to gravity has a magnitude of 3.7 m/s².
The second equation of kinematics gives the relationship between the height reached and time taken by it.
Here, the ball is droped under the action of gravity. The value of acceleration due to gravity on Mars is positive.
We want to know how many seconds the basketball is in the air before it hits the ground. So, the formula is :
t is time taken by the ball to hit the ground
is initial speed of the ball
So, the correct option is (A).
<u>Answer</u>
The acceleration is
to the nearest tenth
<u>Explanation</u>
Since the car was travelling at before it starts to decelerate, the initial velocity is
.
The final velocity is , because the car came to a stop.
The time taken is .
Using the Newton's equation of linear motion,
, we find the acceleration by substituting the known values.
This implies that,
This gives us,
We divide both sides by 15 to get,
or
Answer:
Explanation:
Given two objects are dropped simultaneously
Object A is 10 m higher than object B therefore
Distance covered by object A is given by
is given by
where y=displacement
u=initial velocity
a=acceleration
t=time
for object B
Subtract 1 and 2 we get
i.e. they will travel equal distance in equal time and distance between them remain 10 m until object B hits the ground