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Lady bird [3.3K]
3 years ago
8

A hypothesis MUST be supported by the results. True or false

Chemistry
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

I think this answer is True.

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Dalton theorized that atoms are indivisible and that all atoms of an element are identical. Scientists now know that
malfutka [58]
This is easy the answer is c
8 0
4 years ago
Read 2 more answers
A 500 mL hypertonic saline solution is labeled as consisting of 5.21 % w/w NaCl. Given that the density of salt water is 1.02 g/
kicyunya [14]

<u>Answer:</u> The molarity of saline solution is 0.909 M

<u>Explanation:</u>

We are given:

5.21 w/w % NaCl

This means that 5.21 grams of NaCl is present in 100 grams of solution

To calculate mass of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 1.02 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

1.02g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.02g/mL}=98.04mL

To calculate the moalrity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of NaCl = 5.21 g

Molar mass of NaCl = 58.44 g/mol

Volume of solution = 98.04 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{5.21\times 1000}{58.44g/mol\times 98.04}\\\\\text{Molarity of solution}=0.909M

Hence, the molarity of saline solution is 0.909 M

3 0
3 years ago
A chemist mixes 1.00 g CuCl2 with an excess of (NH4)2HPO4 in dilute aqueous solution . He measures the evolution of 670 J of hea
kaheart [24]

Answer:

\Delta H will be 90054 J

Explanation:

Number of moles = (mass)/(molar mass)

Molar mass of CuCl_{2} = 134.45 g/mol

So, 1.00 g of CuCl_{2} = \frac{1.00}{134.45}mol of CuCl_{2} = 0.00744 mol of CuCl_{2}

0.00744 mol of CuCl_{2} produces 670 J of heat

So, 1 mol of CuCl_{2} produces \frac{670}{0.00744}J of heat or 90054 J of heat

4 0
4 years ago
Phosgene is formed from carbon monoxide and chlorine. At 611 oC, Kc is approximately 16.5 M-1 or L/mol. Calculate Kp (in atm-1)
defon

Answer:

Kp is 0.228/atm

Explanation:

This is the reaction:

CO + Cl<u>₂</u> → CCl₂O

1 mol of carbon monoxide and 1 mol of chlorine produce 1 mol of phosgene.

Formula for Kp which derivates from Kc is:

Kp = Kc (R.T)ⁿᵇ ⁻ ⁿᵃ

Δп = nb (moles in the products) - nₐ(moles in the reactants)

Δп = 1 - 2 = -1

T is T° in K → T°C + 273 = 611°C +273 = 884K

R → Universal constant gas → 0.082 L.atm/mol.K

We replace the data: Kp = 16.5 L/mol (0.082 . 884K)⁻¹ → 0.228/atm

5 0
4 years ago
If a star is shown ti be 33.11 trillion killometers away , how many light year would that be
adoni [48]
Use proportions.

1 lightyear = <span>9.4605284 trillion kilometers
</span><span>x light years </span>≈<span> 33.31 </span>trillion kilometers
<span>
33.31/9.46 = x/1
3.50 </span>≈ x<span>

</span>
8 0
3 years ago
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