2 H₂ + O₂ → 2 H₂O
Al₂O₃ + 6 HCl → 2 AlCl₃ + 3 H₂O
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Explanation:
To balance the chemical equations the number and type of atoms entering the reaction have to be equal to the number an type of atoms leaving the reactions. To do this we add coefficients (usually integer numbers) before each substance.
So we have the following balanced chemical reactions:
2 H₂ + O₂ → 2 H₂O
Al₂O₃ + 6 HCl → 2 AlCl₃ + 3 H₂O
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Learn more about:
balancing chemical equations
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Answer:
Q = 555200 J
Explanation:
∴ mass (m) = 80 kg
∴ c = 3470 J/Kg.K
∴ T1 = 37°C ≅ 310 K
∴ T2 = 39°C ≅ 312 K
⇒ ΔT = T2 - T1 = 312 K - 310 K = 2 K
⇒ Q = (80 Kg)*(3470 J/Kg.K)*(2 K)
⇒ Q = 555200 J ≅ 600000 J ≅ 6 E5 J
Answer:
The correct order of increasing reactivity toward nucleophilic acyl substitution is E < D < C < A < F < B.
Explanation:
The stability of the leaving group best determines the manner of reactivity of carboxylates to nucleophilic substitution after the substitution of the nucleophile to the leaving group. The leaving group should, therefore, be protonated with hydrogen ion in the solution to form a stable molecule. From the given list: The leaving group for A, Ethyl thioacetate will be ethanethiol. For B, Acetyl chloride will be Hydrochloric acid. For C, Sodium acetate will be Sodium Hydroxide. For D, Ethyl acetate will be Ethanol. For E, Acetamide will be Ammonia, and for F, Acetic anhydride will be Ethanoic acid. The reactivity of the substitution reaction is dependent on the stability of these leaving groups. The stability of these leaving groups depends on their pKa, and the more the pKa, the lesser the acidity of the leaving group, and the lower the reactivity. Therefore, considering their pKa: A is 8.5, B is -7, C is 13.8, D is 15.9, E is 36, and F is 4.8. When we rearrange this pKa in descending order, we have E, D. C, A, F, B. Which is also the increased reactivity of the nucleophilic acyl substitution.
Answer:
period 6
Explanation:
If the lanthanides were inserted into the periodic table, they would go into periodic 6.
Their atomic number is between 57 - 71 from element lanthanum to lutetium.
- The elements in this period are 15 in number.
- They are also know as elements in the f-block.
The elements that makes up the series are:
Lanthanum
Cerium
Praseodymium
Neodymium
Promethium
Samarium
Europium
Gadolinium
Terbium
Dysprosium
Holmium
Erbium
Thulium
Ytterbium
Lutetium