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rosijanka [135]
3 years ago
7

Is sodium element a metal nonmetal or metalloid

Chemistry
2 answers:
barxatty [35]3 years ago
7 0
Sodium Na is a metal that goes to the alkali metal with low density and soft
gladu [14]3 years ago
5 0
Sodium Na is a metal that belong to the alkali metal with low density and soft 
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Is a oak tree a invertebrates
viva [34]

Answer:

yes

Explanation:

oak trees don't have vertebrates

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3 years ago
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A student who is performing this experiment pours an 8.50 mL sample of the saturated borax solution into a 10 mL graduated cylin
belka [17]

Answer:

Ksp = 0.1762

Explanation:

Applying

a) moles of HCl added, n= CV=0.5×0.012 = 6×10-3mol

b) since 0.006mol is present in 0.012dm3 of HCl

It implies moles of borax

C) Concentration = 0.706M

Ksp = [0.5]^2[0.706]= 0.176

6 0
3 years ago
A student is standing with their back facing a campfire. The student notices that their back is much warmer than their chest. Th
Mandarinka [93]

Answer:Conduction occurs when energy is passed between objects. The transfer of thermal energy is called heat. Particles of matter are in constant motion.

Explanation:

3 0
2 years ago
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Which one has more mass a bag of cotton balls or a bag of nails and explain
Mama L [17]
You would think that the bag of nails would have more mass but their masses are identical. <span>If you were to put them both in a vacuum chamber and let them fall from a great height, they would fall the same speed. The vacuum chamber would suck all of the air out of the cotton balls, thus making it heavier and weigh the same as the bag of nails.

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6 0
3 years ago
Cu(s) + 4 HNO3 (aq) --&gt; Cu(NO3)2 (aq) + 2NO2 (g) + 2H2O(l)
GREYUIT [131]

Answer:

The percent by mass of copper in the mixture was 32%

Explanation:

The ammount of HNO₃ used is:

mol HNO₃ = volume * concentration

mol HNO₃ = 0.015 l * 15.8 mol/l

mol HNO₃ = 0.237 mol

According to the reaction, 4 mol HNO₃ will react with 1 mol Cu and produce 1 mol Cu²⁺. Since we have 0.237 mol HNO₃, the amount of Cu that could react would be (0.237 mol HNO₃ * 1 mol Cu / 4 mol HNO₃) 0.06 mol. This reaction would produce 0.060 mol Cu²⁺, however, only 0.010 mol Cu²⁺ were obtained, indicating that only 0.010 mol Cu were present in the mixture. This means that the acid was in excess, so we can assume that all copper present in the mixture has reacted.

Since 0.010 mol of Cu²⁺ were produced, the amount of Cu was 0.01 mol.

1 mol of Cu has a mass of 63.5 g, then 0.01 mol has a mass of:

0.01 mol Cu * 63.5 g / 1 mol = 0.635 g.

Since this amount was present in 2.00 g mixture, the amount of copper in 100 g of the mixture will be:

100 g(mixture) * 0.635 g Cu / 2 g(mixture) = 32 g

Then, the percent by mass of Cu (which is the mass of Cu in 100 g mixture) is 32%

6 0
3 years ago
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