How does the wavelength of maximum absorbance relate to color?

1 answer:

5 0

Answer:when a white light falls on an object, the wavelength of maximum absorbance is removed by absorption and the remaining wavelength are reflected to the eye.

Explanation:Furthermore,this relationship entails that the color not absorbed is the color of the object,for example plants are green because they reflect green light and absorb red and blue light.

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Another word for iron oxide?

NARA [144]

Answer:

Hydrated iron(III) oxide, or ferric oxide

Explanation:

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1 year ago

The density of sodium is 968 g/cm3. Suppose you need 250 gm of sodium for an experiment. Which volume of sodium do you need?

Masja [62]

The formula for the density of a substance expressed in mass and volume is rho = mass/volume or p = m/v. Rearranging the formula to isolate volume gives the formula v = m/p. To solve for the problem given, this formula must be used. This gives a solution of:

v = m/p = 250 g/ 968 g/cm^3 = 0.258 cm^3 of sodium

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3 years ago

Suppose you are standing on a scale in an elevator that is accelerating upward. Will the scale read your weight as larger for sm

Marta_Voda [28]

Answer:

following are the solution to this question:

Explanation:

When I stand at such a scale in an elevated that's already rising upwards, its scale would appear to also be 0 because of free fall and would often reveal that weight whenever the lift is stable.

In this, the free fall is also known as the object, that is influenced exclusively by gravity, and an object operating only through the influence of gravity is said to be in a free-fall state.

7 0

3 years ago

A rocket is launched at an angle of 39◦ above the horizontal with an initial speed of 90 m/s. It moves for 7 s along its initial

vagabundo [1.1K]

Answer:

Y=1370.23m

Explanation:

The motion have two moments the first one the time the initial velocity is accelerating then when the engines proceeds to move as a projectile

$a=19 \frac{m}{s^{2} } \\voy=vo*sin(\alpha )\\voy=90*sin(39 )\\y_{o}=0m\\y_{f}=y_{o}+v_{oy}*t+\frac{1}{2}*a*t^{2}\\y_{f}=90*sin(39)*7s+\frac{1}{2}*19\frac{m}{s^{2} }*(7)^{2}\\y_{f}=861.97m$

Now the motion the rocket moves as a projectile so:

$v_{fy}=v_{iy}+a*t\\v_{fy}=90+9.8*7\\v_{fy}=158.6 sin(39)$

Now the final velocity is the initial in the second one

$v_{fy}^{2}=v_{fi}^{2}+2*a*yf \\\\a=g\\$

The maximum altitude Vf=0

$0=v_{fi}^{2}+2*a*yf \\\\yf=\frac{(158.6 sin(39))^{2} }{2*9.8\frac{m}{s^{2} } } \\yf=508.26m$

So total altitude is both altitude of the motion so:

$Y=508.2m+861.97m\\Y=1370.23m$

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3 years ago

In the fall of 2002, a group of scientists at Los Alamos National Laboratory determined that the critical mass of neptunium-237

Llana [10]

The concepts required to solve this problem are those related to density, as a function of mass and volume. In turn, we will use the geometric concept defined for the volume.

The relationship between volume, density and mass is given under the function

$\rho = \frac{m}{V}$