A scientist performs an experiment on an unknown element. She finds that the element forms an ionic bond with beryllium (Be) but
2 answers:
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Answer:
The energy of the wave is 1.435 x 10⁻⁴ J
Explanation:
Given;
area of the window, A = 0.5 m²
the rms value of the field, E = 0.06 V/m
The peak value of electric field is given by;
The average intensity of the wave is given by;
The average power of the wave is given by;
P = I x A
P = (9.569 x 10⁻⁶ W/m²) (0.5 m²)
P = 4.784 x 10⁻⁶ W
The energy of the wave is given by;
E = P x t
E = (4.784 x 10⁻⁶ W)(30 s)
E = 1.435 x 10⁻⁴ J
Therefore, the energy of the wave is 1.435 x 10⁻⁴ J
Answer:
6.30 L
Explanation:
P1 = P, V1 = 4.20 L, T1 = T
P2 = P/3, V2 = ?, T2 = T/2
Where, V2 be the final volume.
Use ideal gas equation
By substituting the values, we get
V2 = 6.30 L