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irina [24]
3 years ago
12

A scientist performs an experiment on an unknown element. She finds that the element forms an ionic bond with beryllium (Be) but

not with lithium (Li). She concludes that the unknown element must belong in group 2 of the periodic table. State whether or not you think this result supports her conclusion, and why
Physics
2 answers:
Bumek [7]3 years ago
4 0

To fill up all of the valence electrons we must have 8 electrons total to have an ionic bond.  In this case Lithium is in group 1 and so only has 1 valence electron and so it can bond with elements from group 17, since 7 + 1 = 8.  However, this unknown element did bond with beryllium, and beryllium is in group 2 so it must bond with an atom that has 6 valence electrons.  The elements that have 6 valence electrons are in group 16 not group 2.  So the result does not support her conclusion.

aivan3 [116]3 years ago
3 0

Answer: The result do not support her conclusion as group 2 elements are metals.

Explanation:

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and forms a positively charged ion called as cation. The element which accepts the electrons is known as electronegative element or non metal and forms a negatively charged ion called as anion.

As both Lithium (Li) and berrylium (Be) are metals, they would combine with a non metal to form ionic bond. Thus the unknown element must be a non metal and should belong to group 14 , 15 , 16 or 17 and not to group 2, which are metals.

Thus The result do not support her conclusion as group 2 elements are metals.

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Un objeto de 1400 g de masa se mueve bajo la acción de una fuerza constante con una aceleración de 0,5 m/s2 , sobre una superfic
igomit [66]

Answer:

if you spoke this in english i can help you out

Explanation:

3 0
3 years ago
A wheel is used to turn a valve stem on a water valve. How much is the mechanical advantage when an effort of 80 lbs. is applied
Ann [662]

Answer:

4

Explanation:

From the question given above, the following data were obtained:

Effort (E) = 80 lbs

Load (L) = 320 lbs

Mechanical advantage (MA) =?

Mechanical advantage is simply defined as the ratio of load to effort. Mathematically, it is expressed as:

Mechanical advantage = Load / Effort

MA = L / E

With the above formula, we can obtain the mechanical advantage as illustrated below:

Effort (E) = 80 lbs

Load (L) = 320 lbs

Mechanical advantage (MA) =?

MA = L / E

MA = 320 / 80

MA = 4

Thus, the mechanical advantage is 4

3 0
2 years ago
On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const
IceJOKER [234]

Answer:

a)

Explanation:

  • Since the car speeds up at a constant rate, we can use the kinematic equation for distance (assuming that the initial position is x=0, and choosing t₀ =0), as follows:

        x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}   (1)

  • Since the car starts from rest, v₀ =0.
  • We know the value of t = 5 sec., but we need to find the value of a.
  • Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:

       a_{c} =\frac{v_{fc}}{t} = \frac{20m/s}{5s} = 4 m/s2  (2)

  • Replacing a and t in (1):

       x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}  = \frac{1}{2}*a*t^{2} = \frac{1}{2}* 4 m/s2*(5s)^{2} = 50.0 m.  (3)

  • Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
  • Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:

       a_{t} =\frac{-v_{to}}{t} = \frac{-20m/s}{10s} = -2 m/s2  (4)

  • Replacing v₀, at and t in (1), we have:

       x_{ft} = 20m/s*10.0s + \frac{1}{2}*(-2 m/s2)*(10.0s)^{2} = 200m -100m = 100.0m   (5)

  • Therefore, as the truck travels twice as far as the car, the right answer is a).
7 0
2 years ago
Your tired 10 lb. baby cousin is cradled in your arms as you're walking back and forth across a 15m room to get her to fall asle
Mashcka [7]

Work done = Force x Distance

Force = 10 lb = 44.5 N

Work Done = 44.5 N x 15 m

= 667.5 N-m

6 0
3 years ago
What equation gives the position at a specific time for an object with constant acceleration? 
malfutka [58]
Given constant acceleration, we can get the final position of an object in terms of both its initial velocity and its acceleration using one of the equations of motion.

The equation that we will use is:
Xf = Xi +  Vi*t + (1/2)*a*t^2
where:
Xf is the final position of the object
Xi is the initial position of the object
Vi is the initial velocity of the object
t is the time
a is the constant given acceleration
4 0
3 years ago
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