An object has an acceleration of 12.0 m/s/s. The mass of the object is doubled while the net force on the object is held constan
1 answer:
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Answer:
(A) 9.5 m/s
(B) 5.225 m
Explanation:
vertical height (h) = 4.7 m
horizontal distance (d) = 9.3 m
acceleration due to gravity (g) = 9.8 m/s^{2}
initial speed of the fish (u) = 0 m/s
(A) what is the pelicans initial speed ?
- lets first calculate the time it took the fish to fall
s = ut +
since u = 0
s =
t =
where a = acceleration due to gravity and s = vertical height
t = = 0.98 s
- pelicans initial speed = speed of the fish
speed of the fish = distance / time = 9.3 / 0.98 = 9.5 m/s
initial speed of the pelican = 9.5 m/s
(B) If the pelican was traveling at the same speed but was only 1.5 m above the water, how far would the fish travel horizontally before hitting the water below?
vertical height = 1.5 m
pelican's speed = 9.5 m/s
- lets also calculate the time it will take the fish to fall
s = ut +
since u = 0
s =
t =
where a = acceleration due to gravity and s = vertical height
t = = 0.55 s
distance traveled by the fish = speed x time = 9.5 x 0.55 = 5.225 m
Answer:
Speed will be 30810 rpm
Explanation:
We have given diameter of the tire d = 24 inch
So radius
We have given linear velocity v = 35 mph
We know that linear velocity is given by
As we know that 1 mile = 63360 inch and 1 hour = 60 min