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katrin [286]
3 years ago
7

An object has an acceleration of 12.0 m/s/s. The mass of the object is doubled while the net force on the object is held constan

t. What will be the new acceleration?
Physics
1 answer:
Aloiza [94]3 years ago
7 0

Answer:

The net force acting on the object is doubled while the mass of the object is held constant. What will be the new acceleration? An object has an acceleration of 12.0 m/s^2. The net force acting on the object is halved (decreased to one half its original value) while the mass of the object is held constant.

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Explanation:

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An RL series circuit is connected to an ac generator with a maximum emf of 20 V. If the maximum potential difference across the
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If the maximum emf of the ac generator is 20 V and the maximum potential difference across the resistor is 16 V Then the maximum potential difference across the inductor is 4 V.

Calculation:

Step-1:

It is given that the RL circuit is connected to a 20 V ac generator. The maximum potential difference across the resistor is 16 V. It is required to find the maximum potential drop across the inductor.

Step-2:

The maximum emf of the generator is equal to the sum of the maximum potential difference across the resistor and the maximum potential difference across the inductor.

Therefore,

The maximum potential difference across the inductor + Maximum maximum potential difference across the resistor = Maximum emf of the generator

Thus,

Maximum maximum potential difference across the inductor + 16 V = 20 V

Therefore,

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Learn more about potential differences across resistor and inductor here,

brainly.com/question/15715072

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2 years ago
How is displacement different from distance?
Anni [7]

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Explanation:

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5 0
4 years ago
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When a certain rubber band is stretched a distance x, it exerts a restoring force of magnitude f = ax, where a is a constant. th
Veseljchak [2.6K]
Given:
F = ax
where
x = distance by which the rubber band is stretched
a =  constant

The work done in stretching the rubber band from x = 0 to x = L is
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Answer:  \frac{aL^{2}}{2}

4 0
4 years ago
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