(A) power = 0.208 kW = 208 watts
(B) energy = 6.6 x 10^{9} joules
Explanation:
energy consumed per day = 5 kWh
(a) find the power consumed in a day
1 day = 24 hours
power = \frac{energy}{time}
power = \frac{5}{24}
power = 0.208 kW = 208 watts
(b) find the energy consumed in a year
assuming it is not a leap year and number of days = 365 days
1 year = 365 x 24 x 60 x 60 = 31,536,000 seconds
energy = power x time
energy = 208 x 31,536,000
energy = 6.6 x 10^{9} joules
Given:
The frequency of the pendulum ( f) = 0.25 Hz.
Total time (t) = 10 s
Concept: Frequency means, the number of oscillation in one second.
Time period is the required time by pendulum to complete one oscillation.
∵ In 1.0 second, number of oscillations = 0.25
∴ In 10.0 second, number of oscillations = (0.25 ×10.0) / 1.0 = 2.5
Hence, the required number of oscillation = 2.5
Answer:
The time taken for the package to reach the ground is 20.6s
Explanation:
Given that the formula of distance is D = S×T where S represents soeed and T is time. So you have to substitute the following values into the formula :
Answer:
∆v = 61.0 m/s
θ = 305°
Explanation:
Given;
initial velocity u= 50.0 m/s angle 270°
Final velocity v = 35.0 m/s angle 180°
∆v = v - u ........1
Resolving into x and y axis;
For y axis
∆vy = vsin180 - usin270
∆vy = 0 - (-50) = 50 m/s
x axis;
∆vx = vcos180 - ucos270
∆vx = -35 - 0= -35m/s
Magnitude of ∆v;
∆v = √(-35^2 + 50^2)
∆v = 61.0 m/s
Direction;
Tanθ = ∆vy/∆vx
θ = taninverse (50/-35)
θ = -55°
θ = 360-55 = 305°
Answer:
change 20 min into hr = <u>0.33 hr</u>
Explanation:
convert= divide the time by 60 because 60 mins make 1 hr
