<span>The trajectory (parabola) for a "particle" of water follows from:
h(t) = v(0) sin(angle) t - 1/2 g t^2
x(t) = v(0) cos(angle) t
From the second equation t = x / (v(0) cos(angle) )
and substitution in the first to eliminate t gives the parabola h(x):
h(x) = x tan(angle) - (g/(2v(0)^2 cos(angle)^2) x^2
h(x) = 0 is solved by x=0 (where the trajectory starts) and at
x = 2 v(0)^2 tan(angle) cos^2(angle) / g
x = 2 v(0)^2 sin(angle) cos(angle) / g
x = v(0)^2 sin(2 angle) / g [[ using sin(2 ) = 2 sin(s) cos(s) ]]
For the first question (the 2.0m distance question) you have therefore to solve for angle the equation
2.0= 2*(6.5)^2 sin(2 angle) / 9.81
sin(2 angle) = 0.23
angle = 1/2 * arcsin(0.23) = 6.65 degrees
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The thermosphere is a layer of Earth's atmosphere. The thermosphere is directly above the mesosphere and below the exosphere. It extends from about 90 km (56 miles) to between 500 and 1,000 km (311 to 621 miles) above our planet.
Your answer is C. hope this helped! :)
Answer:
Explanation:
this graph show the decrease in velocity with time
at time t=0 velocity is 40 m/sec
at time t=12sec velocity is decreases from 40 to 10 m/s
so the acceleration of the object at time=12 sec is
a=v/t
a=Δv/t
Δv=v1-v2=40-10=30 m/s
a=30/12=2.5 m/s^2
Answer:
15.3 m/s
Explanation:
Radius of orbit= 6400+6300 = 12700 km
Circumference of orbit= 2*(22/7)*12700 =79796.45*10^3 m
Now,
Speed= Distance / Time
= 79796.45*10^3/(24*60*3600)
= 15.3 m/s
