Kinetic energy of golf club = 65J,
kinetic energy supplied to golf ball = 20% of 65 = 0.2 * 65 = 13J,
kinetic energy of ball = [mass * Velocity²]/2,
mass = 46gm = 0.046Kg,
[0.046 * V²]/2 = 13, or 0.046 *V² = 26,
V² = 26/0.046 = 565.22,
V = 23.77 m/sec = initial velocity of golf ball after hitting.
Because gravity is constant
<span>the only force acting in free-fall is gravity which points downward at 9.8 m/s</span>
It will lower your Chances of diseases, heart attack, and cholesterol. you can measure your intensity by making sure your body is under a safe amount of stress
Answer:
Vapors
Explanation:
We take into account that all the energy from the lightning has been transformed into steam.

We calculate the amount of energy required by water to convert into steam.



From the lightning we received
of energy, out of which
has been used to convert the water into steam.
Energy left = 
We use this energy to convert steam into vapors.


With this temperature, we can easily interpret that the vapors will be dissociated in hydrogen and oxygen particles.