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Mama L [17]
3 years ago
11

A sample of carbon dioxide gas occuples a volume of 2.5L at standard temperature and pressure (STP). What will be the volume of

a sample of argon gas that has the same number of moles and pressure but twice the absolute temperature?
Chemistry
1 answer:
MArishka [77]3 years ago
5 0

Answer:

The correct answer is 5.0 L

Explanation:

STP are defined as T=273 K and P= 1 atm

By using the ideal gas equation, we can calculate the number of moles (n) of the gas at a volume V=2.5 L:

PV= nRT

⇒n= (PV)/(RT) =(1 atm x 2,5 L)/(0.082 L.atm/K.mol x 273 K)= 0.112 mol

For a sample of argon gas, with the same number of moles (0.112 mol) but twice the temperature (T = 273 K x 2= 546 K):

V= (nRT)/P = (0.112 mol x 0.082 L.atm/K.mol x 546 K)/1 atm = 5.0 L

That is consistent with the fact that when a gas is heated, it expanses. So, if the temperature increases twice, the volume also increases twice.

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1.512 x 10^5 

You simply move the decimal point to the left until you get a number greater than or equal to one, and less than 10, then take that number, and the number of decimal places you moved is the exponent.
5 0
3 years ago
What’s the mass of 1.5 moles of c6h14
Alekssandra [29.7K]
12*6 = 72
1*14 = 14
1.5 * (72+14)
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5 0
2 years ago
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Why are metals generally good conductors of electricity? 1. metals have more protons. 2. metals have strong bonding with other a
Molodets [167]
metal   have   free electrons  in  their   outer  shell  which  make  them  generally  good  conductors  of  electricity. Example  is  the  copper  which   is  used  for  electrical  wiring   since  is  a good  conductor  of  electricity.  copper  with   electronic configuration  of  (Ar)4s2 has  two  free  electrons  in  their  outer  most shell which  allow  it  to  conduct  electricity.
5 0
3 years ago
Read 2 more answers
The partial pressure of cartbon dioxide in the atmgsphere is 0239 toer Caiculate the partial pressure in mm He and atm Rpund eac
Verizon [17]

Answer :

The pressure of carbon dioxide in the atmosphere in mmHg is 0.239mmHg.

The pressure of carbon dioxide in the atmosphere in atm is 3.14\times 10^{-4}atm.

Explanation :

The conversion used for pressure from torr to mmHg is:

1 torr = 1 mmHg

The conversion used pressure from torr to atm is:

1 atm = 760 torr

or,

1torr=\frac{1}{760}atm

As we are given the pressure of carbon dioxide in the atmosphere 0.239 torr. Now we have to determine the pressure of carbon dioxide in the atmosphere in mmHg and atm.

<u>Pressure in mmHg :</u>

As, 1torr=1mmHg

So, 0.239torr=\frac{0.239torr}{1torr}\times 1mmHg=0.239mmHg

Thus, the pressure of carbon dioxide in the atmosphere in mmHg is 0.239mmHg.

<u>Pressure in atm:</u>

As, 1torr=\frac{1}{760}atm

So, 0.239torr=\frac{0.239torr}{1torr}\times \frac{1}{760}atm=3.14\times 10^{-4}atm

Thus, the pressure of carbon dioxide in the atmosphere in atm is 3.14\times 10^{-4}atm.

3 0
2 years ago
In a chemical reaction, exactly 2 mol of substance A react to produce exactly 3 mol of substance B. 2 A ⟶ 3 B How many molecules
Harman [31]

Answer:

There will be produced 1.71 moles of B which contain 1.03×10²⁴ molecules

Explanation:

The example reaction is:

2A → 3B

2 moles of A produce 3 moles of B

If we have the mass of A, we convert it to moles and then, we make the rule of three: 29.2 g / 25.6g/mol = 1.14 moles

Therefore 2 moles of A produce 3 moles of B

1.14 moles of A will produce (1.14 . 3) / 2 = 1.71 moles of B are produced

Now we can determine, the number of molecules

1 mol has NA molecules (6.02×10²³)

1.71 moles have (1.71 . NA) = 1.03×10²⁴ molecules

4 0
3 years ago
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