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OverLord2011 [107]
2 years ago
12

¿Una bombilla de 50 vatios transfiere mas energía por unidad de tiempo que una bombilla de 100 vatios?

Physics
1 answer:
scZoUnD [109]2 years ago
4 0

Answer:

yes it does transfer more energy per unit

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A typical wall outlet voltage in the United States is 120 volts. Personal MP3 players require much smaller voltages, typically 4
alexgriva [62]

Answer:

Number of turns on the secondary coil of the adapter transformer is 10.

Explanation:

For a transformer,

    \frac{V_{s} }{V_{p} } = \frac{N_{s} }{N_{p} }

where V_{s} is the voltage induced in the secondary coil

           V_{p} is the voltage in the primary coil

          N_{s} is the number of turns of secondary coil

         N_{p} is the number of turns of primary coil

From the given question,

    \frac{487*10^{-3} }{120} = \frac{N_{s} }{2464}

⇒    N_{s} = \frac{2462*487*10^{-3} }{120}

            = 9.999733

  ∴   N_{s} = 10 turns

5 0
3 years ago
Read 2 more answers
A light string is wrapped around the edge of the smaller disk, and a 1.50 kg block is suspended from the free end of the string.
LenaWriter [7]

Answer: 7.41 m/s

Explanation: By using the law of of energy, kinetic energy of the brick as it falls equals the potential energy before falling.

Kinetic energy = mv²/2, potential energy = mgh

mv²/2 = mgh

v²/2 = gh

v² = 2gh

v = √2gh

Where g = 9.8 m/s², h = 2.80m

v = √2×9.8×2.8 = 7.41 m/s

7 0
3 years ago
A carmaker has designed a car that can reach a maximum acceleration of 12 meters/second2. The car’s mass is 1,515 kilograms. Ass
Vlada [557]
1) 15 / 12 = 1.25 ratio
2) to increase acceleration  1.25 times (with same F, or same engine) you have to lower mass 1.25 times
3) 1515/1.25 = 1212 kg

choose A

6 0
3 years ago
A simple pendulum is made by tying a 2.44 kg stone to a string 4.57 m long. The stone is projected perpendicularly to the string
alexdok [17]

Answer:

v_{max}=8.2226m/s

Explanation:

The problem is solved using the law of conservation of energy,

So

mgL(1-cos\theta)+\frac{1}{2}mv^2_0=\frac{1}{2}mv^2_{max}

v_{max}=\sqrt{2gL(1-cos\theta)+v^2_0}

v_{max}=\sqrt{2(9.8)(4.57)(1-cos(69.4))+8^2}

v_{max}=8.2226m/s

8 0
3 years ago
What is the frequency in hertz of a signal that repeats 80,000 times within one minute? What is its period?
Harman [31]

1333.3 is the frequency in the hertz of a signal that repeats 80,000 times within one minute. 0.00075 is its period.

The frequency of a repeated event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively.

The length of time it takes for a particle in a medium to complete one full vibrational cycle is the period of a wave. Being a time, a period is measured in time units like seconds, hours, days, or years. The Earth's orbit around the Sun has a duration of around 365 days, and one cycle of the Earth lasts 365 days.

frequency = cycle /second

frequency = 80000 / 60

frequency = 1333.3 hertz

Period = 1 / frequency

Period = 1 / 1,333.3

Period = 0.00075

To know more about  frequency refer to:  brainly.com/question/14472937

#SPJ4

5 0
2 years ago
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