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umka21 [38]
3 years ago
15

My teacher is being weird about it?? every answer i put is wrong someone please help

Chemistry
1 answer:
Kruka [31]3 years ago
7 0
Answer is 146. G/mol
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The quantity 0.202 g has _____________________________ significant<br> figures.
andreyandreev [35.5K]
0.202g has 3 sigfigs
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TRUE OR FALSE: pH measures the amount of hydrogen or hydronium in water
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True

Explanation:

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The room temperature electrical conductivity of a semiconductor specimen is 2.8 x 104 (?-m)-1. The electron concentration is kno
Julli [10]

Answer:

7.43 × 10²⁴ m⁻³

Explanation:

Data provided in the question:

Conductivity of a semiconductor specimen, σ = 2.8 × 10⁴ (Ω-m)⁻¹

Electron concentration, n = 2.9 × 10²² m⁻³

Electron mobility, \mu_n = 0.14 m²/V-s

Hole mobility, \mu_p= 0.023 m²/V-s

Now,

σ = nq\mu_n+pq\mu_p

or

σ = q(n\mu_n+p\mu_p)

here,

q is the charge on electron = 1.6 × 10⁻¹⁹ C

p is the hole density

thus,

2.8 × 10⁴ = 1.6 × 10⁻¹⁹( 2.9 × 10²² × 0.14 +  p × 0.023 )

or

1.75 × 10²³ = 0.406 × 10²² + 0.023p

or

17.094 × 10²² = 0.023p

or

p = 743.217 ×  10²²

or

p = 7.43 × 10²⁴ m⁻³

5 0
4 years ago
A sample of a pure compound that weighs 60.3 g contains 20.7 g Sb (antimony) and 39.6 g F (fluorine). What is the percent compos
Volgvan

Answer:

The percent composition of fluorine is 65.67%

Explanation:

Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.

That is, the percentage composition is the percentage by mass of each of the elements present in a compound.

The calculation of the percentage composition of an element is made by:

percent composition element A=\frac{total mass of element A}{mass of compound} *100

In this case, the percent composition of fluorine is:

percent composition of fluorine=\frac{39.6 g}{60.3 g} *100

percent composition of fluorine= 65.67%

<u><em>The percent composition of fluorine is 65.67%</em></u>

4 0
4 years ago
The initial concentration of reactant in a first-order reaction is 0.27 m. the rate constant for the reaction is 0.75 s-1. what
hjlf
The concentration in  mol/l  of reactant  after  1.5 s  is calculated as  follows

from  first order  integrated  equation

 In (A)t  = - Kt + In (A)o  where
  At = final  concentration =?
A)o =initial  concentration =0.27 M
K =  constant=0.75
T=temperature =  1.5 s

in( A)t = -0.75(1.5) + in(0.27)

In (A)t =-1.125  +-1.31 =-2.435
In(A)t =-2.435

In (A)t  =  e
find the e  value 

 ( A)t is therefore =0.0876  mol/l

5 0
4 years ago
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