Answer:
Explanation:
We need to find the acceleration of the 2 kilogram object. Let's complete this in 2 steps.
<h3>1. Force of 1st Object </h3>
First, we can find the force of the first, 8 kilogram object.
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
The mass of the object is 8 kilograms and the acceleration is 1.6 meters per square second.
Substitute these values into the formula.
Multiply.
<h3>2. Acceleration of the 2nd Object </h3>
Now, use the force we just calculated to complete the second part of the problem. We use the same formula:
This time, we know the force is 12.8 kilograms meters per square second and the mass is 2 kilograms.
Substitute the values into the formula.
Since we are solving for the acceleration, we must isolate the variable (a). It is being multiplied by 2 kg. The inverse of multiplication is division. Divide both sides of the equation by 2 kg.
The units of kilograms cancel.
The acceleration is 6.4 meters per square second.
Answer:
The height of Sears Tower is 1448.5 feet.
Explanation:
<h3>
We apply the free fall formula to the ball:
</h3><h3>
</h3><h3>y: The vertical distance the ball moves at time t </h3><h3>
i: Initial speed
</h3><h3>g=Gravity acceleration=
</h3>
Known information
We know that the vertical distance (y) that the ball moves in 9,5s is equal to height of Sears Tower (h).
Too we know that the ball is released from rest, then,
=0
Height of Sears Tower calculation:
We replace in the equation 1 the data following;
Answer: The height of Sears Tower is 1448.5 ft
Answer:
b. v = 0, a = 9.8 m/s² down.
Explanation:
Hi there!
The acceleration of gravity is always directed to the ground (down) and, near the surface of the earth, has a constant value of 9.8 m/s². Since the answer "b" is the only option with an acceleration of 9.8 m/s² directed downwards, that would solve the exercise. But why is the velocity zero at the highest point?
Let´s take a look at the height function:
h(t) = h0 + v0 · t + 1/2 g · t²
Where
h0 = initial height
v0 = initial velocity
t = time
g = acceleration due to gravity
Notice that the function is a negative parabola if we consider downward as negative (in that case "g" would be negative). Then, the function has a maximum (the highest point) at the vertex of the parabola. At the maximum point, the slope of the tangent line to the function is zero, because the tangent line is horizontal at a maximum point. The slope of the tangent line to the function is the rate of change of height with respect to time, i.e, the velocity. Then, the velocity is zero at the maximum height.
Another way to see it (without calculus):
When the ball is going up, the velocity vector points up and the velocity is positive. After reaching the maximum height, the velocity vector points down and is negative (the ball starts to fall). At the maximum height, the velocity vector changed its direction from positive to negative, then at that point, the velocity vector has to be zero.
Answer:
Explanation:
Explanation: total displacement =3√2m. and total distance covered=14m. I hope this is right and helps u.
Answer:
i think its the third one or second one
