All categories

3 years ago

A 24.0 gram object has a volume of 6.0 mL. What is the density of the object?

Chemistry

2 answers:

dalvyx [7]3 years ago

7 0

Answer:

4 g/mL

Explanation:

The density of a object can be found using the following formula.

$d=\frac{m}{v}$

where m is the mass and v is the volume.

We know that the mass of the object is 24.0 grams and the volume is 6.0 milliliters.

$m= 24 g\\v=6 mL$

Substitute the values into the formula.

$d= \frac{24g}{6mL}$

Divide 24 g by 6 mL.

$d= 4 g/mL$

The density of the object is 4 grams per milliliter.

mart [117]3 years ago

4 0

Answer:

4 g/mL

Explanation:

density = mass/volume

therefore, density = 24/6

ρ = 4 g/mL

You might be interested in

How can scientists use stoichiometry to ensure that commercial products contain the components that manufacturers claim they do?

Rina8888 [55]

Answer:

I know you have been waiting awhile for this question to be answered :)

Stoichiometry is used in industry quite often to determine the amount of materials required to produce the desired amount of products in a given useful equation. Each one of these products requires stoichiometry. There would be no products from these industries without chemical stoichiometry.

Explanation:

Hopefully this helps :D

Sorry you had to wait so long :(

4 0

3 years ago

Hydrogen and oxygen react chemically to form water how much water would form if 14.8grams of hydrogen reacted with 34.8 grams of

pishuonlain [190]

Answer:

There will be formed 39.1935 grams H2O formed

Explanation:

Step 1: The balanced equation

2H2 + 02 → 2H20

Step 2: Given data

mass of hydrogen = 14.8 grams

Molar mass of hydrogen = 2.02 g/mole

mass of oxygen = 34.8 grams

Molar mass of oxygen = 32 g/mole

Step 3: Calculate moles

moles = mass / Molar mass

moles of hydrogen = 14.8g/ 2.02 g/mole = 7.33 moles

moles of oxygen = 34.8g / 32g/mole = 1.0875 moles

For 2 moles hydrogen consumed, we need 1 mole of oxygen.

This means oxygen is the limiting reagens and will be consumed completely. Hydrogen is the reactant in excess, there will remain 5.155 moles of hydrogen

Step 4: Calculate moles of H2O

We see that for 2 moles of H2 consumed, there is needed 1 mole of O2, to produce 2 moles of H2O.

For 1.0875 moles of oxygen consumed, there will be produced 2.175 moles of H2O

Step 5: Calculate mass of water

Mass of H2O = moles of H2O * Molar mass of H2O

Mass of H2O = 2.175 moles * 18.02 g/moles 39.1935 grams

There will be formed 39.1935 grams H2O formed

4 0

4 years ago

Find the density of a cube on Earth that weighs 1.5 kg and has a side-length of 10 cm.

Inga [223]

Answer:

1.5g/cm³

Explanation:

density=mass÷volume

mass= 1.5kg (change into g) = 1500g

volume of the cube = 10×10×10 = 1000cm³

density= divide 1500g÷1000cm = 1.5g/cm³

<h2>Density= 1.5g/cm³</h2>

YOUR WELCOME!

4 0

3 years ago

Michelle has a cup of hot coffee. The liquid coffee weighs 236 grams. Michelle adds a few teaspoons sugar and 25 grams of milk t

sineoko [7]

Answer:

10grams

Explanation:

So it weighs 236 grams added with 25 grams. So it now weighs 261 grams so 10 grams of sugar remains in it.

7 0

3 years ago

A metal ion Mⁿ⁺ has a single electron. The highest energy line in its emission spectrum occurs at a frequency of 2.961 x 10¹⁶ Hz

Whitepunk [10]

Answer:

z≅3

Atomic number is 3, So ion is Lithium ion ( $Li^+$ )

Explanation:

First of all

v=f*λ

In our case v=c

c=f*λ

λ=c/f

where:

c is the speed of light

f is the frequency

$\lambda=\frac{3*10^8}{2.961*10^{16}}\\ \lambda=1.01317*10^{-8} m$

Using Rydberg's Formula:

$\frac{1}{\lambda}=R*z^2*(\frac{1}{n_1^2}-\frac{1}{n_2^2})$

Where:

R is Rydberg constant= $1.097*10^7$

z is atomic Number

For highest Energy:

n_1=1

n_2=∞

$\frac{1}{1.01317*10^{-8}}=1.097*10^{7}*z^2*(\frac{1}{1^2}-\frac{1}{\inf})\\z^2=8.99\\z=2.99$

z≅3

Atomic number is 3, So ion is Lithium ion ( $Li^+$ )

3 0

3 years ago