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Natalka [10]
3 years ago
10

Determine the temperature of 1.42 mol of a gas contained in a 3.00-L container at a pressure of 123 kPa

Chemistry
1 answer:
Rashid [163]3 years ago
6 0

Answer:

The temperature is 30,92K

Explanation:

We use the formula PV=nRT. We convert the unit of pressure in kPa into atm.

101,325kPa----1atm

121kPa-------x=(121,3kPax 1 atm)/101,325kPa=1, 2 atm

PV=nRT---->T= (PV)/(RT)

T=(1,2 atm x 3L)/(1,42 mol x 0,082 l atm/K mol )= 30, 91721058 K

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So first we need to know what the formulas are:

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4 0
3 years ago
The glancing angle (θ) of a Bragg reflection (n = 1) from a set of crystal planes separated by 99.3 pm is 10.42°. Calculate the
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Answer:

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Explanation:

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