Answer:
The angular displacement would be 6 Pi radians or 1080 degrees.
Explanation:
Every individual rotation is 2 Pi (this applies to anything regardless of radius).
Since there are three rotations you are going to multiply 2 Pi by 3.
This will give you 6 Pi which you can convert to equal 1080 degrees (1 Pi = 180 degrees).
<h3><u>
Answer;</u></h3>
B) Not Balanced
B) Sodium
B) Not Equal
The equation is <em><u>not balanced</u></em> because the number of <em><u>sodium atoms</u></em> is <em><u>not equal</u></em> on both sides of the arrow.
<h3><u>Explanation;</u></h3>
- <em><u>According to the law of conservation of mass, the mass of reactants should always be the same as the mass of the products in a chemical equation.</u></em> Therefore, the number of atoms of each element in a chemical equation should always be the same on both sides of the equation, that is the side of reactants and side of products.
- Therefore,<u><em>any chemical equation requires balancing to ensure that the number of atoms of each element is equal in both sides of the equation</em></u>. Balancing is a try and error process that ensures that the law of conservation of mass holds.
- Thus, the balanced chemical equation is;
2Na + Cl2 → 2NaCl
I think the answer is 3 miles because its storming now where I live
Answer:
True
Explanation:
Obesity is a growing concern in children as rates skyrocket to an all time high
A. Medium 1 is air. The refractive index of air is 1.0003. Refractive index is a measure of the bending of a ray of light when passing from one medium to another. If i is the angle of incidence of a ray in vacuum and r is the angle of refraction, the refractive index n is defined as the ratio of the sine angle of incidence to the sine of the angle of refraction; that is, n= sin i/ sin r. Refractive index may also be given by the velocity of light in medium 1 divided by the velocity of light in medium 2.
b. In this case the refractive index = sin 72.5/sin 39.6
= 1.4962
but n = x/ 1.0003 = 1.4962
Therefore; x = 1.4967
Hence the refractive index of medium 2 is 1.4967.
I therefore think that medium 2 is toluene; since it has a similar refractive index.
