A helium balloon with an internal pressure of 1.00 atm and a volume of 4.50 L at 20.0 °C is released. What volume will the ballo

Question

3 years ago

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on occupy at an altitude where the pressure is 0.600 atm and the temperature is –20.0 °C? *

1 answer:

meriva · Answer 1 · 2022-08-25T14:29:02+03:00

Answer:

The balloon will occupy a volume of 6.48 L

Explanation:

<u>Step 1: </u>Data given

internal pressure = 1.00 atm

volume = 4.50 L

Temperature = 20.0 °C

<u>Step 2:</u> Calculate new volume via the ideal gas law

P*V = n*R*T

(P1*V1)/ T1 = (P2*V2)/T2

⇒ with P1 = 1.00 atm

⇒ with V1 = 4.50 L

⇒ with T1 = 20.0 °C = 293 Kelvin

⇒ with P2 = 0.600 atm

⇒ with V2 = TO BE DETERMINED

⇒ with T2 = -20°C = 253 Kelvin

(1.00atm * 4.50 L)/293 Kelvin = (0.600 atm*V2) / 253 Kelvin

0.01536 = 0.00237 V2

V2 = 6.48 L

The balloon will occupy a volume of 6.48 L