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slega [8]
3 years ago
13

What group of elements generally have the lowest second ionization energy?

Chemistry
1 answer:
schepotkina [342]3 years ago
3 0

Answer:

Group 1. Alkali Metals

Explanation:

credit: Difference Between First and Second Ionization Energy

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What is the density of an 84.7 g sample of an unknown substance if the sample occupies 49.6cm cubed
Ahat [919]

Answer:

             1.70 g.cm⁻³

Solution:

Data Given;

                   Mass  =  84.7 g

                   Volume  =  49.6 cm³

                   Density  =  ?

Formula Used;

                   Density  =  Mass ÷ Volume

Putting values,

                   Density  =  84.7 g ÷ 49.6 cm³ 

                   Density  =  1.70 g.cm⁻³

7 0
4 years ago
In which situation are unbalanced forces acting on an object?(1 point)
Alex Ar [27]

Answer:

1. Two people stand on the same side of a large tire. Both people pull the tire with equal force.

2. an object’s ability to not change its motion

3. The car moves forward, while inertia keeps the balloon in place.

4. The unbalanced forces of air resistance and gravity slow the airplane and pull it down.

5. The force acting on the object must be unbalanced.

7 0
3 years ago
A gas has a volume of 30 L at 105 kPa. What pressure is required to compress the gas to 21 L?
Aloiza [94]

Answer: 150 kPa

Explanation:

Given that,

Original volume of gas V1 = 30L

Original pressure of gas P1 = 105 kPa

New pressure of gas P2 = ?

New volume of gas V2 = 21L

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

105 kPa x 30L = P2 x 21L

3150 kPa L = P2 x 21L

P2 = 3150 kPa L / 21 L

P2 = 150 kPa

Thus, 150 kPa of pressure is required to compress the gas

8 0
4 years ago
The specific heat capacity of an unknown metal is 0.343 J/(g•°C). Calculate the energy required to raise the temperature of 224
Margarita [4]

Explanation:

the answer and explanation is in the picture

hope this helps

please like and Mark as brainliest

8 0
4 years ago
If 71.5 moles of an ideal gas is at 5.03 atm at 6.80 °C, what is the volume of the gas?
meriva
Use the clapeyron equation:

T in kelvin : 6.80 + 273 => 279.8 K

R = 0.082 

n = 71.5 moles

P = 5.03 atm

Therefore:

P x V = n x R x T

5.03 x V = 71.5 x 0.082 x 279.8

5.03 x V = 1640.4674

V = 1640.4674 / 5.03

V = 326.13 L

hope ths helps!
5 0
3 years ago
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