The equation K + NaOH => Na + KOH should it react, true or false?

A hydrogen atom with its electron in the n = 6 energy level emits a photon of IR light. Calculate (a) the change in energy of th

geniusboy [140]

Answer:

(a) The change in energy of the atom is --6.0528 X 10⁻²⁰ J

(b) The wavelength of the photon is 32841 Å

Explanation:

E = -kz²/n²

Where;

E is the change in the energy of the atom

k is a constant = 2.179 X 10¹⁸ J

z is the atomic number of hydrogen = 1

n = 6

E = -(1 X 2.179 X 10⁻¹⁸ )/6²

E = -6.0528 X 10⁻²⁰ J

Therefore,the change in energy of the atom is -6.0528 X 10⁻²⁰ J

(b) the wavelength (in Å) of the photon, can be calculated as follows;

E = hc/λ

λ = hc/E

where;

h is Planck's constant = 6.626 X 10⁻³⁴ js

c is the speed of light = 3 X 10⁸ m/s

λ is the wavelength of the photon

λ = (6.626 X 10⁻³⁴ X 3 X 10⁸ )/(6.0528 X 10⁻²⁰)

λ = 3.2841 X 10⁻⁶ m

λ = 32841 Å

Therefore, the wavelength of the photon is 32841 Å

3 0

3 years ago

What are the different ways of how animals reproduce?

Neporo4naja [7]

Answer:

Sexual and Asexual Reproduction

Explanation:

LOL

3 0

3 years ago

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Caffeine, a stimulant in coffee and tea, has a molar mass of 194.19 g/mol and a mass percentage composition of 49.48% C, 5.19% H

lozanna [386]

Answer : The molecular formula of a caffeine is, $C_8H_{10}N_4O_2$

Solution :

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 49.48 g

Mass of H = 5.19 g

Mass of N = 28.85 g

Mass of O = 16.48 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of N = 14 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{49.48g}{12g/mole}=4.12moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.19g}{1g/mole}=5.19moles$

Moles of N = $\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{28.85g}{14g/mole}=2.06moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{16.48g}{16g/mole}=1.03moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{4.12}{1.03}=4$

For H = $\frac{5.19}{1.03}=5.03\approx 5$

For N = $\frac{2.06}{1.03}=2$

For O = $\frac{1.03}{1.03}=1$

The ratio of C : H : N : O = 4 : 5 : 2 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = $C_4H_5N_2O_1=C_4H_5N_2O$

The empirical formula weight = 4(12) + 5(1) + 2(14) + 16 = 97 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

$n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}$

$n=\frac{194.19}{97}=2$

Molecular formula = $(C_4H_5N_2O)_n=(C_4H_5N_2O)_2=C_8H_{10}N_4O_2$

Therefore, the molecular of the caffeine is, $C_8H_{10}N_4O_2$

5 0

4 years ago

The curves represent two possible reaction paths for the decomposition of ammonia, NH3- one can conclude correctly from the grap

DanielleElmas [232]

Hello!

The reaction Heat or ΔH corresponds to the interval A

Reaction Heat is defined as the net change in enthalpy in a chemical reaction. To measure Reaction Heat, the intermediate path doesn't matter, but only the initial and final states.

So, the interval that measures the difference between the initial and final states in this reaction is the interval A, and calculating the enthalpy difference between those two points will give the ΔH of reaction.

Have a nice day!

8 0

3 years ago

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A sample initially contains 1.6 moles of a radioactive isotope. how much of the sample remains after four half-lives?

ad-work [718]

<span>After four half-lives 0.1 mole of the radioactive isotope would remain. If the amount of the isotope that remains after each half life is one half of previously existing amount. Half of 1.6 equals 0.8, half of 0.8 equals 0.4, half of 0.4 equals 0.2, and finally half of 0.2 equals 0.1 mole.</span>

8 0

3 years ago