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Nitella [24]
3 years ago
6

A solid-propellant rocket has chamber pressure of 6.35 atm with propellant density of 3.8 g/cm3 and burn area of 975 cm2 . Find

the total burn time (in seconds) if the propellant mass is 320 kg.
Physics
1 answer:
cupoosta [38]3 years ago
4 0

Answer:

Explanation:

Given:

P = 6.35 atm

= 1.01 × 10^5 × 6.35

= 6.434 × 10^5 N/m^2

As = 975 cm^2

D = 3.8 g/cm^2

M = 320 kg

Since the propellant volume is equal to the cross sectional area, As times the fuel length, the volumetric propellant consumption rate is the cross section area times the linear burn rate, bs , and the instantaneous mass flow rate of combustion, ms gases generated is equal to the volumetric rate times the fuel density, D

ms = D × As × bs

ms ÷ bs = M/L

M/L = 3.8 × 975

= 3705 g/cm

= 3.705 × 10^6 kg/m^3

Pressure = mass × g/area

= mass/length × time^2

t = sqrt(3.705 × 10^6/6.43 × 10^5)

= 2.4 s

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5 0
3 years ago
A charging bull elephant with a mass of 5240 kg comes directly toward youwith a speed of 4.55 m/s. You toss a 0.150- kg rubber b
bearhunter [10]

Answer:

Explanation:

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mass of ball, m2 = 0.150 kg

initial velocity of elephant, u1 = - 4.55 m/s

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Let the final velocity of ball is v2.

Use the formula of collision

v_{2}=\left ( \frac{2m_{1}}{m_{1}+m_{2}} \right )u_{1}+\left ( \frac{m_{2}-m_{1}}{m_{1}+m_{2}} \right )u_{2}

v_{2}=\left ( \frac{2\times 5240}{5240+0.150} \right )(-4.55)+\left ( \frac{0.15-5240}{5240+0.150} \right )(7.81)

v2 = - 16.9 m/s

The negative sign shows that the ball bounces back towards you.

(b) It is clear that the velocity of ball increases and hence the kinetic energy of the ball increases. This gain in energy is due to the energy from elephant.

5 0
3 years ago
In the following reaction, which substance is the precipitate?(NH4)2SO4(aq) + Ba(NO3)2(aq) BaSO4(s) + 2NH4NO3(aq
Delvig [45]
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7 0
3 years ago
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The strength of magnetic field is depends up on the numbers of magnetic field lines per unit area.

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Therefore, inside the bar magnet, the magnetic field points from north to south.

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brainly.com/question/19542022

4 0
2 years ago
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Answer:

s = 23.72 m

v = 21.56 m/s²  

Explanation:

given

time to reach the ground (t) = 2.2 second

we know that

a) s = u t + 0.5 g t²

   u = 0 m/s

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b) impact velocity

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      v = √(2× 9.8 × 23.72)    

      v =  √464.912

      v = 21.56 m/s²  

6 0
3 years ago
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