In the car industry, clay models are used to visualize and test new car designs.

In a black box experiment, when the amount of material exiting a closed system is less than the amount of material entering the

Oksi-84 [34.3K]

When the material that exits is lesser in amount than that of the entering material in a black box experiment, the parts of the system need to be changed.

<h3>What happens in a black box experiment?</h3>

In a black box experiment, the experimenters need to make assumptions regarding the drawing of conclusions. One such conclusion is the amount of material that exits.

If such amount is lesser than the one that enters the system, such experiment concludes that it is the time to change the parts of the system.

Hence, option D holds true regarding the black box experiment.

Learn more about black box experiment here:

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4 0

2 years ago

How long does it take to complete Fort nite: Save The World?

maria [59]

<h3><u>Answer:</u></h3>

Over 8 straight days of playing

<h3><u>Explanation:</u></h3>

200+ hours, if you're a game master

4 0

3 years ago

Read 2 more answers

In an experiment, the local heat transfer over a flat plate were correlated in the form of local Nusselt number as expressed by

zvonat [6]

Answer:

R= 1.25

Explanation:

As given the local heat transfer,

$Nu_x = 0.035 Re^{0.8}_x Pr^{1/3}$

But we know as well that,

$Nu=\frac{hx}{k}\\h=\frac{Nuk}{x}$

Replacing the values

$h_x=Nu_x \frac{k}{x}\\h_x= 0.035Re^{0.8}_xPr^{1/3} \frac{k}{x}$

Reynolds number is define as,

$Re_x = \frac{Vx}{\upsilon}$

Where V is the velocity of the fluid and \upsilon is the Kinematic viscosity

Then replacing we have

$h_x=0.035(\frac{Vx}{\upsilon})^{0.8}Pr^{1/3}kx^{-1}$

$h_x=0.035(\frac{V}{\upsilon})^{0.8}Pr^{1/3}kx^{0.8-1}$

$h_x=Ax^{-0.2}$

<em>*Note that A is just a 'summary' of all of that constat there.</em>

<em>That is $A=0.035(\frac{V}{\upsilon})^{0.8}Pr^{1/3}k$ </em>

Therefore at x=L the local convection heat transfer coefficient is

$h_{x=L}=AL^{-0.2}$

Definen that we need to find the average convection heat transfer coefficient in the entire plate lenght, so

$h=\frac{1}{L}\int\limit^L_0 h_x dx\\h=\frac{1}{L}\int\limit^L_0 AL^{-0.2}dx\\h=\frac{A}{0.8L}L^{0.8}\\h=1.25AL^{-0.2}$

The ratio of the average heat transfer coefficient over the entire plate to the local convection heat transfer coefficient is

$R = \frac{h}{h_L}\\R= \frac{1.25Al^{-0.2}}{AL^{-0.2}}\\R= 1.25$

3 0

3 years ago

Which of the following devices would you expect to consume the most energy for each hour that it operates?

Gennadij [26K]

An electric space heater

4 0

3 years ago

Prebions Now that you are about to complete this module, I'm sure you

kvasek [131]

Explanation:

These are probably the most used tool in any Plumber’s tool box. Pliers are not just another tool for a Plumber, they become an extension of their arms. Most people think that sounds odd, but pliers are more than just a tool to grab or turn things.

These are probably the most used tool in any Plumber’s tool box. Pliers are not just another tool for a Plumber, they become an extension of their arms. Most people think that sounds odd, but pliers are more than just a tool to grab or turn things.Sometimes a piece of copper pipe won’t quite go into a fitting. By using the handle end as a mallet you can gently force it in without damaging/denting the pipe or fittings. Or, when a brute force is needed the jaw end becomes a hammer. On an old pair of pliers I took a grinder to form one side of the handle into a flathead screwdriver/pry bar.

7 0

3 years ago