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xenn [34]
3 years ago
8

Why do engineers need to be particularly aware of the impact of hubris?

Engineering
1 answer:
miv72 [106K]3 years ago
7 0

Answer:

A) Their creations change society.

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Locate the centroid y¯ of the composite area. Express your answer to three significant figures and include the appropriate units
german

Answer:

Please see the attached Picture for the complete answer.

Explanation:

4 0
3 years ago
An enrichment plant has a throughput of 32,000 kg U/day and produces 26,000 kg U as tails. What is the enrichment of the product
torisob [31]

Answer:

1.10 %

Explanation:

The enrichment of the product can be calculated using the following equation:

\frac{W}{P} = \frac{x_{p} - x_{f}}{x_{f} - x_{w}}   (1)

<em>where W: is waste or tails = 26000, P: is the product = 32000, xp: is the wt. fraction of ²³⁵U in product, xf: is the wt. fraction of ²³⁵U in feed = 0.72% and xw: is the wt. fraction of ²³⁵U in waste or tails = 0.25%.      </em>

By solving equation (1) for xp, we can find the enrichment of the product:

x_{p} = \frac {W}{P} \cdot (x_{f} - x_{w}) + x_{f}        

x_{p} = \frac {26000}{32000} \cdot (0.72 - 0.25) + 0.72 = 1.10%  

Therefore, the enrichment of the product is 1.10 %.

I hope it helps you!

7 0
3 years ago
Grinding with the portable disc grinder should not be done in an area which​
emmainna [20.7K]
Nothing flammable of explosive type of material is around
7 0
3 years ago
What’s a trade off? What is one trade-off that the New Balance management makes?
zhannawk [14.2K]

Answer:

A trade-off is a decision to give up one quality to gain another quality. New Balance never lays off employees, but it costs.

Explanation:

8 0
3 years ago
A Coca Cola can with diameter 62 mm and wall thickness 300 um has an internal pressure of 100 kPa. Calculate the principal stres
GarryVolchara [31]

Answer:

\sigma _1=10.33MPa

\sigma _2=5.16MPa

Explanation:

Given that

Diameter(d)=62 mm

Thickness(t)= 300 μm=0.3 mm

Internal pressure(P)=100 KPa

Actually there is no any shear stress so normal stress will become principle stress.This is the case of thin cylinder.The stress in thin cylinder are hoop stress and longitudinal stress .

The hoop stress

\sigma _h=\dfrac{Pd}{2t}

Longitudinal stress

\sigma _l=\dfrac{Pd}{4t}

Now by putting the values

\sigma _h=\dfrac{Pd}{2t}

\sigma _h=\dfrac{100\times 62}{2\times 0.3}

\sigma _h=10.33MPa

\sigma _l=5.16MPa

So the principle stress are

\sigma _1=10.33MPa

\sigma _2=5.16MPa

4 0
3 years ago
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