Answer:
The elevation at the high point of the road is 12186.5 in ft.
Explanation:
The automobile weight is 2500 lbf.
The automobile increases its gravitational potential energy in
. It means the mobile has increased its elevation.
The initial elevation is of 5183 ft.
The first step is to convert Btu of potential energy to adequate units to work with data previously presented.
British Thermal Unit -
Now we have the gravitational potential energy in lbf*ft. Weight of the mobile is in lbf and the elevation is in ft. We can evaluate the expression for gravitational potential energy as follows:
Where m is the mass of the automobile, g is the gravity, W is the weight of the automobile showed in the problem.
is the final elevation and
is the initial elevation.
Replacing W in the Ep equation
Finally, the next step is to replace the variables of the problem.
The elevation at the high point of the road is 12186.5 in ft.
Answer:
Rocks
Explanation:
I am not sure tho bc they are made out of coal and I think coal is a kind of rock
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Answer:
[a]. 0.49.
[2]. 0.536
[c]. 4.15 kmol; 5.84 kmol.
Explanation:
Without mincing words let's dive straight into the solution to the question above.
[a].
The initial external reflux ratio, LD that must be used = [(0.85 - 0.57)/ 0.85 - 0]/ [ 1 - (0.85 - 0.57)/ 0.85 - 0].
The initial external reflux ratio, LD that must be used = 0.329/ 1- 0.329 = 0.49.
[b].
The final external reflux ratio that must be used = [ 0.85 - 0.13/ 0.85 - 0]/ [ 1 - 0.85 - 0.13/ 0.85 - 0].
Hence, the final external reflux ratio that must be used =0.847/ 1 - 0.847 = 5.536.
[c].
The amount of distillate product that is withdrawn:
4 = 0.85 H(t) + 0.8 - 0.08.
H(t) = 4.15 kmol, and the value of Wfinal = 5.84 kmol.
Answer:
It is used for solving optimization problems in which,given some functional,one seeks the function minimizing or minimizing it.
Explanation:
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