Answer:
a = 25 cm/s²
Explanation:
Given,
The mass of the cart, m = 1 Kg
The acceleration of the cart, a = 50 cm/s²
The string with clay hanging off the ramp exerts a force, F on the cart (neglecting the tension in the string)
F = m x a
= 1 Kg X 50 cm/s²
= 50 Kg cm/s²
Hence the force exerted by the clay hanging off the ramp on the cart, F = 50 Kg cm/s²
If the mass of the cart is doubled '2 Kg', the same magnitude of the force acts on the cart.
Therefore, from the equation,
F = m x a
50 Kg cm/s² = 2 Kg x a
a = 50 Kg cm/s² / 2 Kg
= 25 cm/s²
Hence, the acceleration of the cart is, a = 25 cm/s²
Answer: Physical fitness can be defined as the ability of a person to perform daily routine tasks without any ailment.
Explanation:
Dance workouts can help in improving the physical fitness of the person.
This may involve improvement of the cardiovascular strength.
This may also help in improving the strength and endurance of a person.
This improves the stamina, flexibility, and composition of the body.
The dance also helps in maintaining balance and attaining the correct posture.
Answer:
Explanation:
(A) water proofing is designed to keep out soil moisture and liquid water through a concrete structure while damp proofing is a coating on the exterior of a structure so as to stop the transference of ground moisture through concrete.
(B) Water proofing is more appropriate when the water table of the region is higher and there is higher rainfall, it is also more appropriate when there is a presence of hydro-static pressure.
while
Damp proofing is more preferable when there is a drier climate, there is a lower water table, also when there is a well drained soil and also good gravity drain.
Answer:
The second answer from the top, no the energy in the wave pushed the water particles from above the earthquake in the opposite direction.
Explanation:
I believe this is the correct answer. Hope you do well
Answer:
a) 20.81 J
b) 8.29 J
Explanation:
V = iR + L di/dt
where
i = a(1-e^-kt)
for large t
i = V/R
i = 24 / 9.4
i = 2.55 A
so
i = 2.55(1-e^-kt)
di/dt = 2.55 k e^-kt
24 = 24-24e^-kt + 6.4(2.55)k e^-kt
24 = 6.4(2.55) k
k = 24 / (6.4 * 2.55)
k = 24 / 16.32
k = 1.47 = R/L
so
i = 2.55(1-e^-(Rt/L))
current is maximum at great t
i max = 2.55 - 0
energy = (1/2) L i^2
E = (1/2)(6.4)2.55^2
E = 20.81 Joules
one time constant T = L/R and e^-(Rt/L) = 1/e = .368
i = 2.55 (1 - 0.368)
i = 2.55 * 0.632
i = 1.61 amps
energy = (1/2)(6.4)1.61^2
E = 8.29 Joules