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Scrat [10]
4 years ago
15

What do pitch and loudness have in common?

Physics
2 answers:
sladkih [1.3K]4 years ago
6 0

Answer:

both are subject to a person's interpretation.

Dahasolnce [82]4 years ago
4 0

Answer:

it is a subject to a person's interpretation.

Explanation:

i hope this helps!

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What is determined by both mass and velocity
attashe74 [19]
Kinetic energy is the energy of motion. The mass and velocity of an object determines its kinetic energy
4 0
4 years ago
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A Canyon ball is fired from the ground level in angle of 35 from the ground at a speed of 150 m/s ignore air resistance calculat
Virty [35]

The velocity, 50 m/s, has two components - vertical and horizontal velocities.

The vertical component = 50 sin 30 = 25 m/s

The horizontal component = 50 cos 30 = 43.3 m/s

(a)  Let t be the time taken for the vertical component to reach its peak from initial velocity = 25 m/s to its final velocity = 0.

     Using the linear motion equation v = u - gt

     0 = 25 - 10t

     t = 2.5 s

    Time taken to go up and down = 5 s

    Time to hit the ground = 5 s

(b) Horizontal distance dealt x = 43.3 * 5 = 216.5 m

This is not the correct answer, but explains the problem thoroughly.

7 0
3 years ago
If the magnetic field is held constant at 3.0 T and the loop is pulled out of the region that contains the field in 0.2 s, what
kap26 [50]

Answer:

emf = 15 * Area  and if A is given in square meters, the units of the emf will be Volts

Explanation:

Assuming that the area of the loop of current (A) is known, the magnitude of the induced emf can be calculated using Faraday-Lenz's Law:

emf=|-\frac{\Delta\,\Phi}{\Delta \,t} |=|\frac{A\,B}{\Delta \,t}|=|\frac{A\,(3)}{0.2}|=15\,A

and if the area (A) is given in square meters, the emf will directly come in units of Volts.

5 0
4 years ago
When using the magnification equation, a value greater than 1 as the solution for M indicates that the image is_____________.
Alexxandr [17]
Larger than the object.
6 0
4 years ago
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he magnetic flux through a loop of wire decreases from 1.7 Wb to 0.3 Wb in a time of 0.4 s. What was the average value of the in
Pani-rosa [81]

Answer:

Induced emf through a loop of wire is 3.5 V.

Explanation:

It is given that,

Initial magnetic flux, \phi_i=1.7\ Wb

Final magnetic flux, \phi_f=0.3\ Wb

The magnetic flux through a loop of wire decreases in a time of 0.4 s, t = 0.4 s

We need to find the average value of the induced emf. It is equivalent to the rate of change of magnetic flux i.e.

\epsilon=-\dfrac{\phi_f-\phi_i}{t}

\epsilon=-\dfrac{0.3\ Wb-1.7\ Wb}{0.4\ s}

\epsilon=3.5\ V

So, the value of the induced emf through a loop of wire is 3.5 V.

5 0
4 years ago
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